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stira [4]
3 years ago
13

30 students in class 1/5 absent how many students were in class

Mathematics
1 answer:
slava [35]3 years ago
3 0
6 students were in class because the 5 represents on how many groups you need to have
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How do I find a7? Currently getting a even #
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we know that a₁ = 1, and aₙ = aₙ₋₁ + 2, is another way of saying, we add 2 to get the next term, namely, 2 is the common difference.


\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\[-0.5em]
\hrulefill\\
a_1=1\\
d=2\\
n=7
\end{cases}
\\\\\\
a_7=1+(7-1)2\implies a_7=1+12\implies a_7=13

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A bag contains tickets numbered 1 through 5. Use the probability distribution to determine the probability of drawing an odd num
Makovka662 [10]

Answer:

The probability of drawing an odd numbered ticket is 60%.

Step-by-step explanation:

Odd numbered tickets:

Probability of one is 1/5 plus half of 1/5.

P(X = 1) = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}

Probability of 3 is half of 1/5.

P(X = 3) = \frac{1}{10}

Probability of 5 is 1/5. So

P(X = 5) = \frac{1}{5}

Probability of drawing an odd numbered ticket:

p = P(X = 1) + P(X = 3) + P(X = 5) = \frac{3}{10} + \frac{1}{10} + \frac{1}{5} = \frac{4}{10} + \frac{2}{10} = \frac{6}{10} = 0.6

0.6*100% = 60%

The probability of drawing an odd numbered ticket is 60%.

3 0
2 years ago
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