Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
According to the rule of exponents 
, i.e. when two terms are in division with same base , we subtract the exponents
So
Or
x to the 3 fourteenths power
No because if you divide 1.25 by two to find out what the half is in 2.5, it would be .62… and since she wants to buy 2.5 pounds, you've already figured out the .5, so 1.25x2 + .62, it would be 3.12.
Illusion103
For this case we have that the relationship is direct.
Therefore, we have:
Where,
y: distance traveled in kilometers
x: number of liters of fuel
k: proportionality constant
We must look for the value of k. For this, we use the following data:
This car can travel 476 kilometers on 17 liters of fuel.
Substituting values we have:
From here, we clear the value of k:
Therefore, the relationship is:
For 1428 kilometers we have:
Clearing the amount of fuel we have:
Answer:
51 liters of fuel are required for the vehicle to travel 1,428 kilometers
