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Len [333]
3 years ago
8

Find the speed of a 5.6-kg bowling ball that has a kinetic energy of 25.2 J.

Physics
1 answer:
crimeas [40]3 years ago
7 0

                                          Kinetic energy = (1/2) (mass) (speed)²

                                         25.2 J                =  (1/2) (5.6kg) (speed)²

Divide each side
by (2.8 kg) :                     25.2 J / 2.8 kg  =                         speed²

Take the square root
of each side:                   speed = √(9 m²/sec²)

                                                      =  3 m/s .

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Two families meet at the park at 10:00am. Each family uses a different way of transportation to get there. The Gonzalez family l
pav-90 [236]

Firstly, we need to make the times and distance equal to compare.

1hr=60mins
Gonz drove 90km in 60mins,so they would drive 45km in 30 mins dividing it by 2.
Because the Rivs had gone 30km in 30mins, Gonz were faster.

For the adverage speed, we should first add the speed of each family in mph , so 90+60, which equals 150 and divide that by 2 because there are 2 speeds so the average speed is 75mph.

P.S English is my second language so tell me if you don't understand something and I will try and explain.
5 0
3 years ago
What type of energy transfer occurs through light or electromagnetic waves?
Free_Kalibri [48]
Radiation is the transfer of heat energy through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the earth from the sun is in the form of visible light. Light is made of waves of different frequencies.
4 0
3 years ago
Read 2 more answers
The diagram shown represents a block-and-tackle pulley system on which an effort of W Newtons supports a load of 120.0N. If the
natta225 [31]

Answer:

50 N

Explanation:

Efficiency of a machine can't be more than 1, so I assume you mean 40%.  (Remember, efficiency and mechanical advantage are not the same).

Efficiency is the ratio of work out of a system to the work in to the system.

e = Wout / Win

Work is force times distance, so:

e = (Fout × Dout) / (Fin × Din)

Rearranging:

Fin = (Fout × Dout) / (e × Din)

Fin = (Fout / e) × (Dout / Din)

Fin = (Fout / e) / (Din / Dout)

We know that e = 0.40, and Fout = 120 N.  Since there are 6 pulleys, we also know that Din/Dout = 6.

F = (120 N / 0.4) / 6

F = 50 N

5 0
2 years ago
Two charges repel each other with a force. If the magnitude of both charges double, but the distance between them remains consta
-Dominant- [34]

Answer:

C.

Explanation:

4 0
3 years ago
The chain of length L and mass per unit length rho is released from rest on the smooth horizontal surface with a negligibly smal
devlian [24]

Answer:

Part a)

a = \frac{x}{L} g

Part b)

T = \rho x g(1 - \frac{x}{L})

Part c)

v = \sqrt{gL}

Explanation:

Part a)

Net pulling force on the chain is due to weight of the part of the chain which is over hanging

So we know that mass of overhanging part of chain is given as

m = \rho x

now net pulling force on the chain is given as

F = \rho x g

now acceleration is given as

F = Ma

\rho x g = \rho L a

a = \frac{x}{L} g

Part b)

Tension force in the part of the chain is given as

mg - T = ma

\rho x g - T = \rho x a

\rho x(g - a) = T

\rho x (g - \frac{x}{L} g) = T

T = \rho x g(1 - \frac{x}{L})

Part c)

velocity of the last link of the chain is given as

a = \frac{x}{L} g

v\frac{dv}{dx} = \frac{x}{L} g

now integrate both sides

\int v dv = \frac{g}{L} \int x dx

\frac{v^2}{2} = \frac{gL}{2}

v = \sqrt{gL}

3 0
2 years ago
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