Question

A string is tied between two posts separated by 2.4 m. When the string is driven by an oscillator at frequency 567 Hz, 5 points of maximum displacement are observed. What is the speed (in m/s) of a transverse wave on this string

Answer 1

Explanation:

The given data is as follows.

       Length (l) = 2.4 m

       Frequency (f) = 567 Hz

Formula to calculate the speed of a transverse wave is as follows.

                  f = $\frac{5}{2l} \times v$

Putting the gicven values into the above formula as follows.

                  f = $\frac{5}{2l} \times v$

                 567 Hz = $\frac{5}{2 \times 2.4 m} \times v$

                      v = 544.32 m/s

Thus, we can conclude that the speed (in m/s) of a transverse wave on this string is 544.32 m/s.