Ask question

Ask question

All categories

3 years ago

10

Question 11 pts What are the image points of pre-image point (-3, 0) under the following transformations: Reflection over the y-

axis = Rotation of 90 degrees counterclockwise = Rotation of 180 degrees = Reflection over the x-axis = Rotation of 90 degrees clockwise= [ Choose ]

1 answer:

Eva8 [605]3 years ago

3 0

Answer:

(0,3)

Step-by-step explanation:

You might be interested in

Look at the attachment pls!!

Naddika [18.5K]

The terms $-12x^2y$ and $4x^2y$ can be added to $3x^2y$ to result in a monomial.

Step-by-step explanation:

Given term is;

$3x^2y$

A monomial is an algebraic expression that consists of only one term.

So in the given expressions, we will add the terms which have same variables as given terms.

Given options are;

$3xy\\-12x^2y\\2x^2y^2\\7xy^2\\-10x^2\\4x^2y\\3x^3$

The terms $-12x^2y$ and $4x^2y$ can be added to $3x^2y$ to result in a monomial.

4 0

3 years ago

Find the zeros of polynomial function and solve polynomials equations.<br> f(x)=x^2-x-90

victus00 [196]

The zeros are:

10 and -9

(ten and negative-nine)

6 0

3 years ago

What’s the area and perimeter?

Angelina_Jolie [31]

Answer:

•12

Step-by-step explanation:

fInd Little bit at end by pythogotous and find are of shaded the find areo of non shaded and take away with shaded triangle

4 0

2 years ago

Identify an equation in point-slope form for the line perpendicular to y = –4x – 1 that passes through (–2, 7).

Harlamova29_29 [7]

To get a perpendicular line, your slopes will equal -1 when multiplied...this means if we multiply - 4 x (1/4), we get out slope to use for the next step.

Y - Y1 = M(X - X1) passes through (-2, 7)
Y - 7 = 1/4(X - (-2))
Y - 7 = 1/4(X + 2)
Y - 7 = 1/4X + 1/2
+7 + 7
Y = 1/4X + 7.5

6 0

3 years ago

Read 2 more answers

Find the equation of the line passing through the points (1,5) and (3,9)

Arada [10]

Answer:

$\boxed{\sf{2}}$

Step-by-step explanation:

Use the slope formula.

$\underline{\text{SLOPE:}}$

$\Longrightarrow: \sf{\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{Rise}{Run} }$

$\sf{y_2=9}\\\\\\\sf{y_1=5}\\\\\\\sf{x_2=3}\\\\\\\sf{x_1=1}$

$\sf{\dfrac{9-5}{3-1} }$

Solve.

$\sf{\dfrac{9-5}{3-1}=\dfrac{4}{2}=\boxed{\sf{2}}$

<u>Therefore, the slope is 2, which is our answer.</u>

I hope this helps. Let me know if you have any questions.

8 0

1 year ago