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attashe74 [19]
3 years ago
7

Georgia bought a pair of flip-flops that cost $3.46 and a pair of slip-on shoes that cost $9.87 She paid a total of $what for th

e two pairs of shoes.
Mathematics
2 answers:
ohaa [14]3 years ago
8 0

Answer: The cost for the two pairs of shoes is $13.33.

Step-by-step explanation:

Since we have given that

Cost of pair of flip flops = $3.46

Cost of pair of slip on shoes = $9.87

We need to find the cost of two pairs of shoes.

Cost of two pairs of shoes = Cost of pair of flip flops + Cost of pair of slip on shoes

Cost=3.46+9.87=\$13.33

Hence, the cost for the two pairs of shoes is $13.33.

balu736 [363]3 years ago
7 0
$13.33
Only information they give you is the prices unless i'm missing something.
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9x,2,8y

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Find the volume of combined solid from the given figure.​
tankabanditka [31]

Answer:

1944 cubic cm

Step-by-step explanation:

Find the answer by figuring out the volumes independently for each figure.  After doing that, add both volumes together to get the full volume.

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What integer is equivalent to 25 3/2
antiseptic1488 [7]
<span><span><u>Answer</u>
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

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3 0
3 years ago
Read 2 more answers
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
3 years ago
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