What type of math is this?
Try this option:
1. rule: P(E)+P(not E)=1.
2. according to the rule above
P(not E)=1-P(E)=1-0.3=0.7;
P(E)=1-P(not E)=(100-65)%=35%.
Using the z-distribution, it is found that the margin of error is of 0.059.
We are given the standard deviation for the population, hence the <em>z-distribution</em> is used.
<h3>What is the margin of error for a z-confidence interval?</h3>
It is given by:

In which:
is the population standard deviation.
In this problem, the parameters are:
.
- Confidence level of 0.90, hence, using a z-distribution calculator, the critical value is z = 1.645.
Then:



The margin of error is of 0.059.
You can learn more about the z-distribution at brainly.com/question/12517818