To solve the problem it is necessary to take into account the concepts related to the Reynolds Number and the Force of drag on the bodies subjected to a Fluid.
The Reynolds number for the Prototype and the Model must therefore be preserved,
Re-arrange for the speed of the model we have,
Our values at 20°C would be given of the table of Physical Properties of water where
While for the values previous given we have
And we have a Ratio between the prototype and the model of 16:1, then
PART B) To calculate the ratio of the drag force now we have to,
Replacing with our values we have,
Therefore the ratio of drag force for prototype and model is 0.5016
Answer:
t= 9.79 hr
Explanation:
Given that
V= 3.5 V
Capacity= 4 Amp-hour
We know that
V= IR
V= Voltage
I =Current
R=Resistance
V = I R
The total voltage on the batteries will be 2 V
2 x 3.5 = I x 10
I= 0.7 A
We know that Power P
P = V I
P = 0.7 x 7
P =4.9 W
4 A.h and 12 volt power supply = 4 x 12 = 48 W.hr
So time of drain t
4.9 t = 48
t= 9.79 hr
Answer:
Resulting heat generation, Q = 77.638 kcal/h
Given:
Initial heat generation of the sphere,
Maximum temperature,
Radius of the sphere, r = 0.1 m
Ambient air temperature, = 298 K
Solution:
Now, maximum heat generation, is given by:
(1)
where
K = Thermal conductivity of water at
Now, using eqn (1):
max. heat generation at maintained max. temperature of 360 K is 24924
For excess heat generation, Q:
where
Now, 1 kcal/h = 1.163 W
Therefore,