Answer:
theoretical fracture strength = 16919.98 MPa
Explanation:
given data
Length (L) = 0.28 mm = 0.28 × 10⁻³ m
radius of curvature (r) = 0.002 mm = 0.002 × 10⁻³ m
Stress (s₀) = 1430 MPa = 1430 × 10⁶ Pa
solution
we get here theoretical fracture strength s that is express as
theoretical fracture strength = 
.............................1
put here value and we get
theoretical fracture strength = 
theoretical fracture strength = 
theoretical fracture strength = 16919.98 MPa
Answer:
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Explanation:
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Answer:
the rate of heat loss by convection across the air space = 82.53 W
Explanation:
The film temperature
to kelvin = (5 + 273)K = 278 K
From the " thermophysical properties of gases at atmospheric pressure" table; At 
= 278 K ; by interpolation; we have the following
→ v 13.93 (10⁻⁶) m²/s
→ k = 0.0245 W/m.K
→ ∝ = 19.6(10⁻⁶)m²/s
→ Pr = 0.713
The Rayleigh number for vertical cavity
= 
= 
For the rectangular cavity enclosure , the Nusselt number empirical correlation:
h = 1.99 W/m².K
Finally; the rate of heat loss by convection across the air space;
q = hA(T₁ - T₂)
q = 1.99(1.4*0.96)(20-(-10))
q = 82.53 W
Answer:
Part a : The SI unit of σ is Pascal.
Part b : The pressure is 414.28 psi.
Explanation:
Part a
The equation is given as
As per the dimensional analysis
![M=[N-m]\\y=[m]\\l=[m^4]](https://tex.z-dn.net/?f=M%3D%5BN-m%5D%5C%5Cy%3D%5Bm%5D%5C%5Cl%3D%5Bm%5E4%5D)
So the equation becomes
![\sigma =\frac{[N-m][m]}{[m^4]}\\\sigma =\frac{[N][m^2]}{[m^4]}\\\sigma =\frac{[N]}{[m^{4-2}]}\\\sigma =\frac{[N]}{[m^{2}]}\\](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Cfrac%7B%5BN-m%5D%5Bm%5D%7D%7B%5Bm%5E4%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%5Bm%5E2%5D%7D%7B%5Bm%5E4%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%7D%7B%5Bm%5E%7B4-2%7D%5D%7D%5C%5C%5Csigma%20%3D%5Cfrac%7B%5BN%5D%7D%7B%5Bm%5E%7B2%7D%5D%7D%5C%5C)
As the dimensions are of pressure so the SI unit of σ is Pascal.
Part b
Pressure in US customary base units is given in psi so
So
So the pressure is 414.28 psi.
