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3 years ago

Which part does NOT rotate when the engine is running and the clutch pedal is depressed?

Engineering

1 answer:

erik [133]3 years ago

7 0

Answer:

your answer would be B-(Clutch-Disk)

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Which state did NOT have people that got sick from the

12345 [234]

New jersey has the least amount out of all of these.
california : 98
new jersey : 17
tennessee : 64
florida : 49

3 0

3 years ago

What is the difference between absolute and gage pressure?

Len [333]

Explanation:

Step1

Absolute pressure is the pressure above zero level of the pressure. Absolute pressure is considering atmospheric pressure in it. Absolute pressure is always positive. There is no negative absolute pressure.

The expression for absolute pressure is given as follows:

$P_{ab}=P_{g}+P_{atm}$

Here, $P_{ab}$ is absolute pressure, $P_{g}$ is gauge pressure and $P_{atm}$ is atmospheric pressure.

Step2

Gauge pressure is the pressure that measure above atmospheric pressure. It is not considering atmospheric pressure. It can be negative called vacuum or negative gauge pressure. Gauge pressure used to simplify the pressure equation for fluid analysis.

8 0

3 years ago

There is a dispute between the multiple parties storing financial transaction data on a blockchain over the validity of a transa

spayn [35]

Answer:

dgjkkkkkkkfdcvv

Explanation:

hjklllgfddsssssyjjjkkkk

p.s sorry

5 0

2 years ago

What are the maximum weights for single, tandem and 5-axle combinations?

belka [17]

Hauling Vehicles that include a semitrailer manufactured prior to or in the model year of 2024, and registered in Illinois prior to January 1, 2025, having 5 axles with a distance of 42 feet or less between extreme axles, may not exceed the following maximum weights: 20,000 pounds on a single axle; 34,000 pounds

7 0

3 years ago

Six forces act on a beam that forms part of a building's

IrinaVladis [17]

Answer:

Explanation:

write each force in terms of magnitude and directions

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let

FA = FA sin (110) + FA cos (110)

FB = 20 sin (270) + 20 cos (270)

FC = 16 sin (140) + 16 cos (140)

FD = 9 sin (40) + 9 cos (40)

FE = 20 sin (270) + 20 cos (270)

FG = FG sin (50) + FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110) + 0 + 16 sin (140) + 9 sin (40) + 0 + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110) + 0 + 10.285 + 5.785 + 0 + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110) + 16.070 + FG sin (50) = 0

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

FG = 15.3 kN

7 0

3 years ago