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hjlf
3 years ago
13

I need the help of identifying the constant term and numerical coefficient in this expression

Mathematics
1 answer:
aalyn [17]3 years ago
8 0
<h2>Answer:</h2><h2>constant term =4</h2><h2>numerical coefficient =2</h2><h2>FOLLOW ME FOR CLEARING YOUR NEXT DOUBT</h2>

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Math question:
Vera_Pavlovna [14]

Answer: 102

Step-by-step explanation:

4 0
3 years ago
One side of a triangle is 7 feet longer than the second side. The third side is 2 feet longer than the second side. The perimete
sleet_krkn [62]

Answer: second 11

first 18

Second 13

Step-by-step explanation:

4 0
3 years ago
(Partially Done!) Verify the identity and show your work.
vladimir1956 [14]
Throughout all of these steps I'm only going to alter the left hand side (LHS). I am NOT going to change the right hand side (RHS) at all.

Before I change the LHS of the original equation, let's focus on the given identity
cot^2(x) + 1 = csc^2(x)

Since we know it's an identity, we can subtract 1 from both sides and the identity would still hold true
cot^2(x) + 1 = csc^2(x)
cot^2(x) + 1-1 = csc^2(x)-1
cot^2(x) + 0 = csc^2(x)-1
cot^2(x) = csc^2(x)-1

So we'll use the identity cot^2(x) = csc^2(x)-1

---------------------------------------------

Now onto the main equation given

cot^2(x) + csc^2(x) = 2csc^2(x) - 1
cot^2(x) + csc^2(x) = 2csc^2(x) - 1 .... note the term in bold
csc^2(x)-1 + csc^2(x) = 2csc^2(x) - 1 .... note the terms in bold
[ csc^2(x) + csc^2(x) ] - 1 = 2csc^2(x) - 1
[ 2csc^2(x) ] - 1 = 2csc^2(x) - 1
2csc^2(x) - 1 = 2csc^2(x) - 1

The bold terms indicate how the replacements occur.

So the original equation has been proven to be an identity because the LHS has been altered to transform into the RHS
7 0
3 years ago
Which of the following is a complex number?<br> OA. 3V+<br> B. 5 - 207<br> oc. 9 - 1<br> OD. -88 - 4
Bogdan [553]
A complex number would be OA. 3V+
6 0
3 years ago
Please help! i'll give brainliest and 5 stars
klio [65]

Answer:

Step-by-step explanation:

x/2 = 20

*2      *2     (2 cancels)

 x = 40

6 0
3 years ago
Read 2 more answers
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