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deff fn [24]
3 years ago
13

What is the electric flux φ through each of the six faces of the cube?

Physics
1 answer:
olasank [31]3 years ago
7 0
For the complete answer to the question above,  <span>phi = q/(6*epsilon(0)) 

Gauss' law tells us that the total flux through a closed surface, in this case, a cube, is equal to the charge enclosed, q, divided by epsilon(0). 

phi = q/epsilon(0) 

Since the point charge is in the center of the cube, each face will have an equal amount of flux going through it, i.e. one-sixth. 

This gives us 

phi = q/(6*epsilon(0)) </span>
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