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deff fn [24]
3 years ago
13

What is the electric flux φ through each of the six faces of the cube?

Physics
1 answer:
olasank [31]3 years ago
7 0
For the complete answer to the question above,  <span>phi = q/(6*epsilon(0)) 

Gauss' law tells us that the total flux through a closed surface, in this case, a cube, is equal to the charge enclosed, q, divided by epsilon(0). 

phi = q/epsilon(0) 

Since the point charge is in the center of the cube, each face will have an equal amount of flux going through it, i.e. one-sixth. 

This gives us 

phi = q/(6*epsilon(0)) </span>
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A simple pendulum with a length of 2.23 m and a mass of 6.74 kg is given an initial speed of 2.06 m/s at its equi- librium posit
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Answer:

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b)   K = 14.3 J

c)   φ = 0.444 rad

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  T = 2π\sqrt{\frac{l}{g} }

        Where l: Pendulum’s length

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  T = 2π\sqrt{\frac{2.23}{9.8} }

  T = 2.997 s

b) Total energy

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  K = \frac{mv^{2} }{2}

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  K = 14.3 J

c) Maximum angular displacement

  φ = cos^{-1}(1-\frac{E}{mgl} )

  φ = cos^{-1}(1-\frac{14.3}{(6.74)(9.8)(2.23)} )

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The cross-sectional area of the wire is given by:

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