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ycow [4]
3 years ago
10

A roller coaster starts down a hill at 10 m/s. Three seconds later, its speed is 32 m/s. What is the roller coaster’s accelerati

on?
Question 1 options:

-7.3 m/s


-7.3 m/s2


3 m/s

3 m/s 2
Save
Question 2 (2 points) Question 2 Unsaved
Natalie accelerates her skateboard along a straight path from 4 m/s to 0 m/s in 25.0 s. Find the acceleration.

Question 2 options:

-6.25 m/s2


0.16 m/s2


-0.16 m/s2


6.25 m/s2

Save
Question 3 (2 points) Question 3 Unsaved

Find the average acceleration of a northbound subway train that slows from 12 m/s to 9.6 m/s in 0.9 s

Question 3 options:

-2.7 m/s2


2.7 m/s2


-2.7 m/s


2.7 m/s

Save
Question 4 (2 points) Question 4 Unsaved
What is a chicken’s rate of acceleration that speeds up from 4 mph (mi/h) to a top speed of 9 mi/h in 0.5 hr?

Question 4 options:

2.5 mi/h/s


-2.5 mi/h/s


2.5 mi/h2


10 mi/h2

Save
Question 5 (2 points) Question 5 Unsaved
Which units would be appropriate to measure Acceleration?

Question 5 options:

m/s with direction


m/s2


Kg (m/s)


m/s

Save
Physics
1 answer:
DaniilM [7]3 years ago
3 0
1) a = Δv/Δt
a = (32-10)/3
a = 7.33 m/s²

2) a = (0 - 4)/25
a = -0.16 m/s²

3) a = (9.6 - 12) / 0.9
a = -2.7 m/s²

4) a = (9-4)/0.5
a = 10 mi/h²

5) m/s²
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miss Akunina [59]

Answer:

Explanation:

The rocky planets include Mercury, Venus, Earth, and Mars. they are made up of rocks and metals and have solid surfaces.They are the closest four planets to the Sun. The gas giants are  Neptune, Uranus, Saturn, and Jupiter. they are further from the sun and are in the outer part of the solar system. I hope this helps!

6 0
3 years ago
You are standing in an elevator that is accelerating upward at 1m/s². Which of the following pairs of forces is an action-reacti
Lostsunrise [7]

Answer:

B The force that the floor of the elevator exerts on you and the force that you exert on the floor of the elevator

Explanation:

A. is incorrect because the force of gravity on you will always stays the same while the force of the elevator exerts on you changes as it takes you upward

B. is correct in accordance to Newton's 3rd law of action and reaction forces.

C. is incorrect because gravity force stays the same while the force that you exerts on the floor change as elevator moving upward.

D. is incorrect although it states Newton's 1st law. However there can still be pair of forces (part B) that could counter balance each other among other forces.

5 0
3 years ago
Fill in the blank: energy can never be created nor destroyed just _ or _
Alja [10]
I know one is transformed, not sure about another
4 0
3 years ago
A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The coppe
marin [14]

Answer:

a) T_f=305.7049\ K

b) \Delta S=313.51\ J.K^{-1}

Explanation:

Given:

  • mass of copper, m_c=2.64\ kg
  • initial temperature of copper, T_{ic}=400\ K
  • specific heat capacity of copper, c_c=385\ J.kg^{-1}.K^{-1}
  • mass of water, m_w=4\ kg
  • initial temperature of water, T_{iw}=300\ K
  • specific heat capacity of water, c_w=4200\ J.kg^{-1}.K^{-1}

a)

<u>∵No heat is lost in the environment and the heat is transferred only between the two bodies:</u>

Heat rejected by the copper = heat absorbed by the water

2.64\times 385\times (400-T_f)= 4\times 4200\times (T_f-300)

T_f=305.7049\ K

b)

<u>Now the amount of heat transfer:</u>

Q=m_c.c_c.(T_{ic}-T_{f})

Q=2.64\times 385\times (400-305.7049)

Q=95841.5841\ J

∴Entropy change

\Delta S=\frac{dQ}{T}

\Delta S=\frac{95841.5841}{305.7049}

\Delta S=313.51\ J.K^{-1}

5 0
4 years ago
A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is oriented
oee [108]

Answer:

Magnetic flux, \phi=2.22\times 10^{-3}\ Wb

Explanation:

It is given that,

Magnitude of the magnetic field, B = 0.078 T

Radius of circular loop, r = 0.1 m

The field is oriented at an angle of θ = 25° with respect to the normal to the surface. The magnetic flux through the surface is given by :

\phi=BA\ cos\theta

\phi=0.078\times \pi \times (0.1)^2\ cos(25)

\phi=0.00222\ Wb

or

\phi=2.22\times 10^{-3}\ Wb

So, the magnitude of magnetic flux through the surface is 2.22\times 10^{-3}\ Wb. Hence, this is the required solution.

4 0
4 years ago
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