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Lady_Fox [76]
4 years ago
11

A cation is any atom or group of atoms with

Chemistry
2 answers:
anastassius [24]4 years ago
7 0

Answer:

a positive charge

Explanation:

cation positive

anion negative

pshichka [43]4 years ago
4 0

A cation is an atom or group of atoms that have a positive charge.

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How many electrons in an atom could have these sets of quantum numbers?
Alecsey [184]
Ml=−2,−1,0,+1,+2.
<span>Since each of these orbitals can hold a maximum of </span>two electrons<span>, one having spin-up and one having spin-down, a total of </span>10 electrons<span> can share the quantum numbers n = 4 and l = 2</span>
8 0
3 years ago
How much energy (joules) is needed to heat 250 grams of copper from 22 °C to 99 °C? The specific heat capacity (C) of copper is
Naddik [55]

Answer:

7430.5 Joules (7.4*10^4 Joules)

Explanation:

Q=mc∆T

where Q is energy in Joules.

Now m=250 g

c= 0.386 J/g°C

∆T = 99 - 22 = 77 °C

plugging the values in gives

Q=250*0.386*77=7430.5 Joules

(7.4*10^4 Joules, if 2 significant figures)

5 0
3 years ago
The volume of a gas is 450 mL when its pressure is 1.00 atm. If the temperature of the gas does not change, what is the
NikAS [45]

Answer: 0.225 atm

Explanation:

For this problem, we have to use Boyle's Law.

Boyle's Law: P₁V₁=P₂V₂

Since we are asked to find P₂, let's manipulate the equation.

P₂=(P₁V₁)/V₂

P_{2} =\frac{(1.00atm)(0.45L)}{2.00L}

With this equation, the liters cancel out and we will be left with atm.

P₂=0.225 atm

6 0
3 years ago
GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g
JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of H_2 gas and 1 mole of Br_2 liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ

Divide the equation by 2.

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

4 0
3 years ago
What is the concentration, in mass percent (m/m), of a solution prepared from 50.0 g nacl and 150.0 g of water?
Nataly [62]
Mass of solute ( m1 ) = 50.0 g

mass of solvent ( m2 ) = 150.0 g

Therefore:

m/m = ( m1 / m1 + m2 )

m/m = ( 50.0 / 50.0 + 150.0 )

m/m = ( 50.0 / 200 )

m/m = 0.25
8 0
3 years ago
Read 2 more answers
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