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Reptile [31]
3 years ago
15

What is the percent copmosition of chromium in CrF3

Chemistry
1 answer:
zepelin [54]3 years ago
5 0
47.707% is the answer
You might be interested in
What does halogen mean?
Mademuasel [1]
A Halogen is a group (or a column) on the periodic table. It contains fluorine, chlorine, bromine, and astatine!
6 0
3 years ago
How many O atoms are in 4C₆H₁₂O₆
ipn [44]

Number of O atoms : 24

<h3>Further explanation</h3>

Given

C₆H₁₂O₆ compound

Required

Number of atoms

Solution

A molecular formula  shows the number of atomic elements in compound.  

The empirical formula is the smallest comparison of the atoms

Glucose-C₆H₁₂O₆ is composed of 3 elements, namely C, H, and O.

The number of atoms in a compound can usually be seen from the subscript number after the atom and the reaction coefficient shows the number of molecules

So number of O atoms :

= 4 x 6 = 24 atoms

6 0
3 years ago
How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?
weeeeeb [17]

Answer : The number of moles of solute Ca(OH)_2 is, 0.0788 moles.

Explanation : Given,

Molarity = 0.225 M

Volume of solution = 0.350 L

Formula used:

\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}

\text{Moles of }Ca(OH)_2=0.0788mol

Therefore, the number of moles of solute Ca(OH)_2 is, 0.0788 moles.

7 0
3 years ago
10. How many g of Cu(OH)2 can be made from 9.1 x 1025 atoms of O?
il63 [147K]
Molar mass Cu(OH)₂ = 97.561 g/mol

97.561 g Cu(OH)₂ --------------- 6.02x10²³ atoms
  ? g Cu(OH)₂ -------------------- 9.1x10²⁵ atoms

mass = 9.1x10²⁵ * 97.561 / 6.02x10²³

mass = 8.87x10²⁷ / 6.02x10²³

mass = 14734.2 g

hope this helps!
8 0
3 years ago
In the PhET simulation window, click the radio button labeled Mystery in the Blocks menu on the right-hand side of the screen. U
Yuliya22 [10]

Answer:

B, D, E, C, A

Explanation:

We have 5 blocks with their respective masses and volumes.

Block            Mass            Volume

  A                65.14 kg       103.38 L

  B                0.64 kg         100.64 L

  C                4.08 kg         104.08 L

  D                3.10 kg          103.10 L

  E                 3.53 kg         101.00 L

The density (ρ) is an intensive property resulting from dividing the mass (m) by the volume (V), that is, ρ = m / V

ρA = 65.14 kg / 103.38 L = 0.6301 kg/L

ρB = 0.64 kg / 100.64 L = 0.0064 kg/L

ρC = 4.08 kg / 104.08 L = 0.0392 kg/L

ρD = 3.10 kg / 103.10 L = 0.0301 kg/L

ρE = 3.53 kg / 101.00 L = 0.0350 kg/L

The order from least dense to most dense is B, D, E, C, A

4 0
2 years ago
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