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Sedbober [7]
3 years ago
7

5. Desde 100 g de un compuesto formado por carbono, hidrogeno y oxígeno, se obtiene 39,132 g de agua y 95,656 g de CO2. Determin

e:
A. La fórmula empírica del compuesto.
Chemistry
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

      CH_2O_2

Explanation:

The question in English is:

<em>5. From 100 g of a compound formed by carbon, hydrogen and oxygen, 39.132 g of water and 95.656 g of CO₂ are obtained. Determine:</em>

<em />

<em>A. The empirical formula of the compound.</em>

<h2>Solution</h2>

All the carbon of the compound ends as carbon in the CO₂ and all the hydrogen in the compound ends in the water.

<u>1. C in CO₂</u>

Divide the mass of CO₂ by its molar mass and multiply by the molar mass of C:

        96.656g\times \dfrac{12.011g/mol}{44.01g/mol}=26.379gC

<u>2. H in H₂O</u>

Divide the mass of H₂O by its molar mass and multiply by 2 times the molar mass of H:

        39.132g\times \dfrac{(2\times 1.008)g/mol}{18.015g/mol}=4.379gH

<u>3. Calculate O by difference</u>

     100g-26.379g-4.379g=69.242gO

<u>4.Divide the mass of each element by the corresponding atomic mass to find the number of moles of the element</u>

  • C: 26.379g / (12.011g/mol) = 2.196 mol
  • H: 4.379g / (1.008g/mol) = 4.344 mol
  • O: 69.242g / (15.999g/mol) = 4.328 mol

<u />

<u>5. Divide by the least number of moles</u>

  • C: 2.196/2.196 = 1
  • H: 4.344 / 2.196 ≈ 2
  • O: 4.328 / 2.196 ≈ 2

Those are the subscripts of the empirical formula:

<u>6. Empirical formula</u>

         CH_2O_2

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The atomic radius of main group elements generally increases down a group because as there are more electrons they are farther away from the nucleus and the electrons closer to the nucleus shield the outer electrons from the protons for attraction.

8 0
3 years ago
If gatorade g series, endurance formula, contains 14 grams of carbohydrate per 8 ounces, how many ounces should a basketball pla
Mashcka [7]

Based on recommended amount of carbohydrate, a basketball player should consume about 17 - 34 ounces of gatorade g series during the hour-long game.

<h3>How many ounces of endurance formula gatorade g series, endurance formula should a basketball player consume during an hour-long game if it contains 14 grams of carbohydrate per 8 ounces?</h3>

Carbohydrates are food substances metabolized easily by the body to produce energy.

Given that the recommended amount of carbohydrate to consume to maintain performance is 30–60 g/h.

Also 14 grams of carbohydrate found in 8 ounces of the drink.

30 g of carbohydrate will be present in 30 × 8/14 = 17.1 ounces of gatorade g series

60 g of carbohydrate will be present in 60 × 8/14 =34.3 ounces of gatorade g series.

Therefore, a basketball player should consume about 17 - 34 ounces of gatorade g series during the hour-long game.

Learn more about carbohydrates at: brainly.com/question/797978

8 0
2 years ago
Pleassssdseee help meee
SpyIntel [72]
I believe it’s Non polar molecule
8 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
1 point
lawyer [7]

Answer:

B

Explanation:

you're moving the decimal 8 spots to the left so it can only be B

6 0
2 years ago
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