Answer:
bcoz iron displaces copper and form the solution iron sulfide
Explanation:
when we dip iron nail in copper sulfate solution,then iron starts reacting with the solution and due to displacement reaction between them iron is stronger metal than copper so it displaces copper and form iron sulfide:
CuSO4+3Fe---->Fe3SO4+Cu
Answer:
ΔH° = 840 kJ/mol
Explanation:
Let's consider the following balanced reaction:
2 AgNO₃(aq) + CaCl₂(aq) ⇄ 2 AgCl(s) + Ca(NO₃)₂
Then, we need to know the moles of both reactants:
AgNO₃: n = 0.200 mol/L × 0.0500 L = 0.0100 mol
CaCl₂: n = 0.100 mol/L × 0.0500 L = 0.00500 mol
According to the balanced equation we need 2 moles of AgNO₃ per each mole of CaCl₂, and this coincides with the experimental data, so there is no limiting reactant. Let's use AgNO₃ to find out how many moles of AgCl are produced.
![0.0100molAgNO_{3}.\frac{2molAgCl}{2molAgNO_{3}} =0.0100molAgCl](https://tex.z-dn.net/?f=0.0100molAgNO_%7B3%7D.%5Cfrac%7B2molAgCl%7D%7B2molAgNO_%7B3%7D%7D%20%3D0.0100molAgCl)
Now, we can calculate the total amount of heat released using the following expression:
Q = c × m × ΔT
where,
c is the heat capacity of the solution
m is the mass of the solution
ΔT is the change in temperature (26.0 °C - 25.0°C = 1.00 °C)
Since the volume is 100.0 mL (50.0 mL + 50.0 mL) and the density is 1.05 g/mL, we can calculate the mass of the solution like:
m = 1.05 g/mL × 100.0 mL = 105 g
Then,
![Q=c \times m \times \Delta T=4.20 J/g.\° C \times 105 g \times 1.00\° C=8.40 \times 10^{3} J=8.40kJ](https://tex.z-dn.net/?f=Q%3Dc%20%5Ctimes%20m%20%5Ctimes%20%5CDelta%20T%3D4.20%20J%2Fg.%5C%C2%B0%20C%20%5Ctimes%20105%20g%20%5Ctimes%201.00%5C%C2%B0%20C%3D8.40%20%5Ctimes%2010%5E%7B3%7D%20J%3D8.40kJ)
Finally,
![\Delta H \° = \frac{8.40kJ}{0.0100mol} =840kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%20%5C%C2%B0%20%3D%20%5Cfrac%7B8.40kJ%7D%7B0.0100mol%7D%20%3D840kJ%2Fmol)
Yes it is for example look at Iodine and Tellurium.
Hope this helps :).
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