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2 years ago

How can I do this with the function (x+2)/x-3

1 answer:

3 0

Y= (x+2)/(x-3)
This function exists for x≠3 (value that render the denominator nil)
If x →3 , then y→ ∞, then:
Vertical Asymptote x=3

Horizontal asymptotes ↔ lim y = 1
x→∞
Horizontal asymptotes y =1

x-intercept: for y= 0, x = -2

y-intercept: for x= 0, y = -2/3

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The diameter of a circle has endpoints whosever coordinates are R(-2,2) and S(4,2). find the center of the circle

lisov135 [29]

Hello!

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2 years ago

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telo118 [61]

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Step-by-step explanation:

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morpeh [17]

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2 years ago

Question 7<br> Solve the Equation:<br> D(7) = ?<br> D= 8

Degger [83]

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2 years ago

Using a sheet of graph paper, solve the following system of equations graphically. Be sure to show any work, use a straight edge

madam [21]

Answer:

Step-by-step explanation:

Given system is

$\left \{ {{x+y=0} \atop {x-y+2=0}} \right.$

If we graph, the solution would be the interception point between these two lines, because each linear equation represents a line. The lines are attached.

In the graph, you can observe that the solution is the point (-1,1), that is x = -1 and y = 1.

Now, if we want to solve this system by another method, we can just sum both equations and solve for <em>x</em>

$\left \{ {{x+y=0} \atop {x-y+2=0}} \right.$

$2x+2=0\\x=\frac{-2}{2}=-1$

Then, we replace this value in one equation to find the other value

$x+y=0\\-1+y=0\\y=1$

Therefore, the solution is (-1,1)

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2 years ago