Work is defined as the amount of force done multiplied by the distance it was applied. Since it is already given that the object of interest (a box of groceries) was lifted up 1 meter by a force of 5 newtons, work done can be solved using the following formula:
Work = Force * distance
Work = 5 N * 1 meter
Work = 5 N*m = 5 J
The formula is F = ( q1 * q2 ) / r ^ 2
<span>where: q is the individual charges of each ion </span>
<span>r is the distance between the nuclei </span>
<span>The formula is not important but to explain the relationship between the atoms in the compounds and their lattice energy. </span>
<span>From the formula we can first conclude that compounds of ions with greater charges will have a greater lattice energy. This is a direct relationship. </span>
<span>For example, the compounds BaO and SrO, whose ions' charges are ( + 2 ) and ( - 2 ) respectively for each, will have greater lattice energies that the compounds NaF and KCl, whose ions' charges are ( + 1 ) and ( - 1 ) respectively for each. </span>
<span>So Far: ( BaO and SrO ) > ( NaF and KCl ) </span>
<span>The second part required you find the relative distance between the atoms of the compounds. Really, the lattice energy is stronger with smaller atoms, an indirect relationship. </span>
<span>For example, in NaF the ions are smaller than the ions in KCl so it has a greater lattice energy. Because Sr is smaller than Ba, SrO has a greater lattice energy than BaO. </span>
<span>Therefore: </span>
<span>Answer: SrO > BaO > NaF > KCl </span>
Answer:
2.1406 ×
m/sec
Explanation:
we know that energy is always conserved
so from the law of energy conservation

here V is the potential difference
we know that mass of proton = 1.67×
kg
we have given speed =50000m/sec
so potential difference 
now mass of electron =9.11×
so for electron

so the velocity of electron will be 2.1406×
m/sec
Answer:
= 1,386 m / s
Explanation:
Rocket propulsion is a moment process that described by the expression
- v₀ =
ln (M₀ / Mf)
Where v are the velocities, final, initial and relative and M the masses
The data they give are the relative velocity (see = 2000 m / s) and the initial mass the mass of the loaded rocket (M₀ = 5Mf)
We consider that the rocket starts from rest (v₀ = 0)
At the time of burning half of the fuel the mass ratio is that the current mass is
M = 2.5 Mf
- 0 = 2000 ln (5Mf / 2.5 Mf) = 2000 ln 2
= 1,386 m / s
Answer:
V = x/t
where:
x = distance [m]
t = time [s]
V = velocity [m/s]
Explanation:
Speed is defined as the distance travelled by a body in a given time interval. The velocity or speed is a vector, that is, it has magnitude and direction.
By virtue of its vector character, the direction of the displacement and the module, which is called speed, must be considered to define the velocity.
<u>Average speed</u>
The average speed is defined as the change of position over a given time interval. It is calculated by dividing the displacement vector (Δx) between the time interval (Δt) used.
<u>Instant speed</u>
Instantaneous velocity is a vector tangent to the trajectory, corresponding to the derivative of the vector position relative to time.
It allows to know the speed of a mobile that moves on a trajectory when the interval of time is infinitely small, being then the space traveled also very small, representing a point of the trajectory. Instant velocity is always tangent to the trajectory.