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Alex
3 years ago
8

Describe what may happen when ripples on a pond encounter a large Rock in the water

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0
Hello

<span>The ripples may reflect, and they might diffract around the edges
</span>
Have a nice day
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Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t
Readme [11.4K]

Answer: 3.66(10)^{33}kg

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity \omega of the planet P1 with a period T=750years=2.36(10)^{10}s:

\omega=\frac{2\pi}{T}=\frac{V_{1}}{R} (1)

Where:

V_{1}=40.2km/s=40200m/s is the velocity of planet P1

R is the radius of the orbit of planet P1

Finding R:

R=\frac{V_{1}}{2\pi}T (2)

R=\frac{40200m/s}{2\pi}2.36(10)^{10}s (3)

R=1.5132(10)^{14}m (4)

On the other hand, we know the gravitational force F between the star S with mass M and the planet P1 with mass m is:

F=G\frac{Mm}{R^{2}} (5)

Where G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

In addition, the centripetal force F_{c} exerted on the planet is:

F_{c}=\frac{m{V_{1}}^{2}}{R^{2}} (6)

Assuming this system is in equilibrium:

F=F_{c} (7)

Substituting (5) and (6) in (7):

G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}} (8)

Finding M:

M=\frac{V^{2}R}{G} (9)

M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}} (10)

Finally:

M=3.66(10)^{33}kg (11) This is the mass of the star S

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4 years ago
Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.
Mariana [72]

Answer: The answer would be no reaction.

Explanation:

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Find the current flowing through the following circuit
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Answer:

0.5

Explanation:

calculating the total resistance for the both the parallel and the series resistors then later using the ohm's law formulae V=IR to calculate current.

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Why does changing the shape on an object have no affect on the density of that object?
Anna11 [10]
It is because change in the Mass of the object balances the change in the Volume of the object equally...........
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A stream of plasma? Solar wind, coronal mass ejection
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Answer:

coronal mass ejection

Explanation:

Solar wind is something that has to do with magnetism,

CME is " is a significant release of plasma and accompanying magnetic field from the solar corona," that often follows solar flares.

https://en.wikipedia. org/wiki/Coronal_mass_ejection

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