All categories

3 years ago

What is the value of in if the remainder of n/4 is 3?

Mathematics

2 answers:

vichka [17]3 years ago

8 0

Answer:

The value of N is 7

Step-by-step explanation:

4+3 is 7 and 7-4 is 3 therefore the value of N is 7

Mnenie [13.5K]3 years ago

4 0

Answer:

<h2>Value of "n" = 7</h2>

Step-by-step explanation:

$Since,$

$4+3=7$

$And$

$7-4=3$

$The~value~of~n~is=7$

$hope~this~helps~you!$

$Have~a~blessed~day!$

You might be interested in

Can someone help me answer questions

ANEK [815]

Add 6 to both sides
2m2+7m+6=0

5 0

3 years ago

Help me somebody if you want to help me

elena55 [62]

Answer:

A=πr²=π·3²≈28.27433

To find the area of a circle, use the equation πr²

The image is a bit blurry so from what I saw r (radius) is 3 otherwise you can use this equation if r is not 3.

If π was replaced with 3.14 the answer is 28.26 ft².

8 0

3 years ago

A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yield

Leno4ka [110]

Answer:

0.762 = 76.2% probability that this shipment is accepted

Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17 randomly selected pens

This means that $n = 17$

(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is $P(X \leq 2)$ when $p = 0.1$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167$

$P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315$

$P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762$

0.762 = 76.2% probability that this shipment is accepted

8 0

3 years ago

How many hours are in 2 weeks if it is about 23.93 hours in a day?

klemol [59]

2 weeks (14 days) X 23.93 hours a day = 335.02 hours in 2 weeks

so 14 x 23.93 = 335.02

hope I helped:)

3 0

3 years ago

Help pleaseeeeee desperate

elena-s [515]

B can be either 2/3 or -2/3

5 0

3 years ago