Answer:
A car would need to be moving with a velocity of 28.86 m/s for its acceleration to be numerically equal to the acceleration due to gravity.
Explanation:
Radial acceleration for an object in circular motion is given by
α = v²/r
α = g = 9.8 m/s²
v = ?
r = 85 m
9.8 = v²/85
v² = 9.8 × 85 = 833
v = 28.86 m/s
Answer:
T₂=659.25 K
Explanation:
Given that
W= 25 J
Qr = 20 J
T₁ = 20⁰ = 20 +273 = 293 K
The minimum temperature of the hot reservoir = T₂
If the engine is Carnot engine then
Qa= W+ Qr
Qa=25 + 20 J
Qa= 45 J



T₂=659.25 K
Therefore the temperature of hot reservoir will be 659.25 K
I would say the the answer is 7.20 because if subtract the 8.00 grams from the 15.20 g you would get 7.20. Am I correct, please ley me know
Answer:
It helps us to know or be aware of some things that happen regular and teaches us about laws that guide us
The answer to this question is B....hope this helps.