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2 years ago

If a system reliability of 0.998 is required, what reliability of two components in series is required?

Physics

1 answer:

Yakvenalex [24]2 years ago

3 0

Two components in the series have dependability of $0.996$ .

We need both two components to function in order to determine the engine's reliability. Since each component has dependability of $0.998$ , we must determine the likelihood that both components will function in order to determine the engine's reliability.

The possibility that a product, system, or service will function as intended for a predetermined amount of time, or that it will run faultlessly in a predetermined environment, is known as reliability.

By multiplying each of the $10$ reliability coefficients, we may calculate this probability:

$P = 0.998^2 = 0.996004$

P is equal to $0.9966$ after being rounded to three decimal places.

The engine has a dependability rating of $0.996$ .

Hence,

Two components connected in series have dependability of $0.996$ .

<h3>What is the compound of reliability ?</h3>

Reliability and failure probability are complimentary, or $F= 1 - R$ .

In various cases, the distinctive qualities of a series arrangement will be demonstrated. $R = R 1 R 2$ is the resultant reliability of two components.

A component's reliability is assessed in light of the application for which it will be utilised. An operational profile gives a description of the situation. Software reliability can be calculated or measured.

To learn more about compound of reliability, Visit:

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3 years ago

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Answer:

$a_c=2.0196\times 10^{13}\ m/s^2$

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Explanation:

m = Mass of proton = $1.67\times 10^{-27}\ kg$

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$P=2\pi r\\\Rightarrow r=\frac{P}{2\pi}\\\Rightarrow r=\frac{7000}{2\pi}\ m$

$a_c=\frac{v^2}{r}\\\Rightarrow a_c=\frac{\left(1.5\times 10^8\right)^2}{\frac{7000}{2\pi}}\\\Rightarrow a_c=2.0196\times 10^{13}\ m/s^2$

Centripetal acceleration is $2.0196\times 10^{13}\ m/s^2$

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3 years ago

The area around a charged object that can exert a force on other charged objects is an electric ___

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Answer is:

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3 years ago

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3 years ago

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