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Vlad [161]
2 years ago
12

If a system reliability of 0.998 is required, what reliability of two components in series is required?

Physics
1 answer:
Yakvenalex [24]2 years ago
3 0

Two components in the series have dependability of 0.996.

We need both two components to function in order to determine the engine's reliability. Since each component has dependability of 0.998, we must determine the likelihood that both components will function in order to determine the engine's reliability.

The possibility that a product, system, or service will function as intended for a predetermined amount of time, or that it will run faultlessly in a predetermined environment, is known as reliability.

By multiplying each of the 10 reliability coefficients, we may calculate this probability:

P = 0.998^2 = 0.996004

P is equal to 0.9966 after being rounded to three decimal places.

The engine has a dependability rating of 0.996.

Hence,

Two components connected in series have dependability of 0.996.

<h3>What is the compound of reliability ?</h3>

Reliability and failure probability are complimentary, orF= 1 - R.

In various cases, the distinctive qualities of a series arrangement will be demonstrated. R = R 1 R 2 is the resultant reliability of two components.

A component's reliability is assessed in light of the application for which it will be utilised. An operational profile gives a description of the situation. Software reliability can be calculated or measured.

To learn more about compound of reliability, Visit:

brainly.com/question/14972427

#SPJ4

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In the context of energy transfers with hot and cold reservoirs, the sign convention is that _______________.
Likurg_2 [28]

Answer:

B. QC > 0; QH < 0

Explanation:

Given that there are two reservoir of energy.

Sign convention for heat and work :

1.If the heat is adding to the system then it is taken as positive and if heat is going out from the system then it is taken as negative.

2. If the work is done on the system then it is taken as negative and if the work is done by the system then it is taken as positive.

From hot reservoir heat is going out that is why it is taken as negative

Q_H

From cold reservoir heat is coming inside the reservoir that is why it is taken as positive

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That is why the answer will be

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8 0
3 years ago
A 594 Ω resistor, an uncharged 1.3 μF capacitor, and a 6.53 V emf are connected in series. What is the current in milliamps afte
ivanzaharov [21]

Answer:

6.88 mA

Explanation:

Given:

Resistance, R = 594 Ω

Capacitance = 1.3 μF

emf, V = 6.53 V

Time, t = 1 time constant

Now,

The initial current, I₀ = \frac{\textup{V}}{\textup{R}}

or

I₀ = \frac{\textup{6.53}}{\textup{594}}

or

I₀ = 0.0109 A

also,

I = I_0[1-e^{-\frac{t}{\tau}}]

here,

τ = time constant

e = 2.717

on substituting the respective values, we get

I = 0.0109[1-e^{-\frac{\tau}{\tau}}]

or

I = 0.0109[1-2.717^{-1}]

or

I = 0.00688 A

or

I = 6.88 mA

5 0
3 years ago
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