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Tcecarenko [31]
3 years ago
9

How much does horizontal velocity change each second as it moves through the air?

Physics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Well, Bianca, I'll tell ya. You really haven't told us enough to completely define exactly what's going on here.  In fact, now that I look at it carefully, you've told us nothing at all ... only asked a question based on zero given information.

IF you're talking about an object like a baseball or a rock or another projectile of some kind, and IF the object has no jet engines on it, and IF it has been tossed, launched, thrown, or otherwise sent on its way to somewhere other than the place it left from, and IF it's OK to ignore the effects of air resistance, then ...

-- the only force acting on the object is the force of gravity

-- gravity only points down

-- gravity has no effect on horizontal velocity

-- horizontal velocity is <em>constant</em>, and <em>doesn't change </em>as time goes on.

But IF any of these things is different, then you can forget everything I said.  I'm just guessing.

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What’s the difference between applied and pure research
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Answer:

Pure research is conducted without any specific goal in mind. Applied research is conducted in order to solve a specific and practical problem, unlike pure research. Hope this helped.

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3 years ago
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4 years ago
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S Four point charges each having charge Q are located at the corners of a square having sides of length a. Find expressions for(
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The total electric potential at the center of the square due to the four charges is V  = √2Q/πÈa.

<h3>What do you mean by electric potential? </h3>

The amount of work needed to move a unit charge from a reference point to a specific point against an electric field. It's SI unit is volt.       

V = kq/r

Where V represents electric potential, K is coulomb constant, q  is Charge and r is distance between any  two around charge to the point charge.

Electric potential at O due to four charges is given by,

V = 4KQ/ r

where, r = √2a/2 = a/√2

V = 4k × Q√2/a

V  = √2Q/πÈa

The total electric potential at the center of the square due to the four charges is V  = √2Q/πÈa.

To learn more about electric potential refer to:

brainly.com/question/12645463

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3 0
2 years ago
A cheetah can run at 105 feet per second, but only for 7 seconds, at which time the animal must stop and rest. A fully rested ch
shepuryov [24]

Answer:

5 seconds

Explanation:

The straight line distance between (0, 0) and the antelope's position (x, y) at time t can be found using distance formula:

d² = x² + y²

d² = (-39 + 40t)² + (228 + 30t)²

d² = 1521 - 3120t + 1600t² + 51984 + 13680t + 900t²

d² = 53505 + 10560t + 2500t²

The cheetah can run a total distance of:

105 * 7 = 735

The time t at this distance is:

735² = 53505 + 10560t + 2500t²

540225 = 53505 + 10560t + 2500t²

0 = -486720 + 10560t + 2500t²

0 = -24336 + 528t + 125t²

t = 12, -16.224

t can't be negative, so t = 12.

Therefore, the cheetah can wait 5 seconds before it has to start running.

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4 years ago
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