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alexandr1967 [171]
3 years ago
10

Which predator is typically found in Central Africa (but occasionally at geocode 34.043021, -118.2668356) and slays its opponent

s through a rapid application of venomous strikes
Chemistry
1 answer:
noname [10]3 years ago
6 0
I believe it is a black mamba.
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If the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10, how much does the pH change:
andreev551 [17]

Answer:

The pH changes by 2.0 if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

Explanation:

To solve this problem we use the<em> Henderson-Hasselbach equation</em>:

  • pH = pKa + log [A⁻]/[HA]

Let's say we have a weak acid whose pKa is 7.0:

  • pH = 7.0 + log [A⁻]/[HA]

If the [A⁻]/[HA] ratio is 10/1, we're left with:

  • pH = 7.0 + log (10/1)
  • pH = 7.0 + 1
  • pH = 8.0

Now if the ratio is 1/10:

  • pH = 7.0 + log (1/10)
  • pH = 7.0 - 1
  • pH = 6.0

The difference in pH from one case to the other is (8.0-6.0) 2.0.

<em>So the pH changes by 2.0</em> if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

<u>Keep in mind that no matter the value of pKa, the answer to this question will be the same.</u>

3 0
3 years ago
A sample of P 2 O 4 contains 181 . g of phosphorus. Calculate the mass of the sample in pounds
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Answer:

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7 0
3 years ago
A substance is found to consist of 1.900g of silver, 0.250g of nitrogen, and 0.850g of oxygen. what is the percent by mass of ox
Galina-37 [17]
The  percentage  by mass  of  oxygen  in  the  compound

find  the total  mass=(  1.900+  0250 +0.850) =  3
the  percentage  mass  mass of  oxgyen/total  mass  x100

that  is  (0.850/3)  x100=28.33%
7 0
3 years ago
If I initially have a gas at a pressure of 12 kPa, a volume of 23 liters, and a temperature of 200 K, and then I raise the press
sertanlavr [38]

Answer:

The new volume of gas would be 30 L.

Explanation:

This is an example of a Combined Gas Laws problem.

5 0
3 years ago
What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, c2h6? in this reaction,
Vitek1552 [10]

Balance equation for combustion of ethane will be:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

To balance the equation:

1. Balance the number of carbon atom on both side:

C₂H₆(g) + O₂(g)--------> CO₂(g) + H₂O(g)

1. balance the number of carbon on both side, as in reactant there are 2 but in product one,

so , multiply the CO₂, by 2 in the product.

2. Balance the number of hydrogen on both side as in reactant the number of hydrogen is 3 but in product it is 6 so, multiplythe number of  H₂O by 3,

so multiply the number of  H₂O by 3 in product.

3. Balance the number of oxygen on both side , as 1 and 2 step increases the number of oxygen and it becomes 7 , so to balance the number of oxygen on both side by mutiplying the  number of  O₂ by 7/2 in reactant .

4. Now, doubling the equation will give balance equation that is:

2C₂H₆(g) + 7O₂(g)--------> 4CO₂(g) + 6H₂O(g)

8 0
3 years ago
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