Answer:
x = 3.25; y = 5.5; angle measures are (cw from bottom left): 96, 84, 96
Step-by-step explanation:
The two angles above the horizontal line form a linear pair, so they are supplementary. Their measures add to 180 deg. That let's you find the value of x.
28x - 7 + 24x + 18 = 180
52x + 11 = 180
52x = 169
x = 169/52
x = 3.25
Now use the lower left angle and the upper right angle. They are vertical angles, so they are congruent. That allows you to solve for y.
12y + 30 = 24x + 18
We know that x = 3.25.
12y + 30 = 24(3.25) + 18
12y + 30 = 78 + 18
12y = 66
y = 66/12
y = 5.5
I don't know what the problem is asking for since you don't show.
x = 3.25; y = 5.5; angle measures are (cw from bottom left): 96, 84, 96
To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:
![Area = Length \times Width](https://tex.z-dn.net/?f=Area%20%3D%20Length%20%5Ctimes%20Width)
<u>Rectangle (a)</u>
![Area = 4x \times 4](https://tex.z-dn.net/?f=Area%20%3D%204x%20%5Ctimes%204)
![Area = 16x](https://tex.z-dn.net/?f=Area%20%3D%2016x)
<u>Rectangle (b)</u>
![Area = 11 \times x](https://tex.z-dn.net/?f=Area%20%3D%2011%20%5Ctimes%20x)
![Area = 11x](https://tex.z-dn.net/?f=Area%20%3D%2011x)
<u>Rectangle (c)</u>
![Area = 2 \times 8x](https://tex.z-dn.net/?f=Area%20%3D%202%20%5Ctimes%208x)
![Area = 16x](https://tex.z-dn.net/?f=Area%20%3D%2016x)
<u>Rectangle (d)</u>
![Area = 16x \times 1](https://tex.z-dn.net/?f=Area%20%3D%2016x%20%5Ctimes%201)
![Area = 16x](https://tex.z-dn.net/?f=Area%20%3D%2016x)
Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
Answer:
58 students
Step-by-step explanation:
Given
![Total = 85](https://tex.z-dn.net/?f=Total%20%3D%2085)
![French = 27](https://tex.z-dn.net/?f=French%20%3D%2027)
![Geometry = 51](https://tex.z-dn.net/?f=Geometry%20%3D%2051)
![History = 38](https://tex.z-dn.net/?f=History%20%3D%2038)
![None = 5](https://tex.z-dn.net/?f=None%20%3D%205)
![All = 2](https://tex.z-dn.net/?f=All%20%3D%202)
Required
Students that take only 1 subjects
The attached image illustrates the question.
For French only (x), we have:
![x + 7 -2+10-2+2=27](https://tex.z-dn.net/?f=x%20%2B%207%20-2%2B10-2%2B2%3D27)
![x + 15=27](https://tex.z-dn.net/?f=x%20%2B%2015%3D27)
Collect like terms
![x =- 15+27](https://tex.z-dn.net/?f=x%20%3D-%2015%2B27)
![x =12](https://tex.z-dn.net/?f=x%20%3D12)
For Geometry only (y), we have:
![y+10-2+15-2+2=51](https://tex.z-dn.net/?f=y%2B10-2%2B15-2%2B2%3D51)
![y+23=51](https://tex.z-dn.net/?f=y%2B23%3D51)
Collect like terms
![y=-23+51](https://tex.z-dn.net/?f=y%3D-23%2B51)
![y=28](https://tex.z-dn.net/?f=y%3D28)
For History only (z), we have:
![z +15-2+7-2+2=38](https://tex.z-dn.net/?f=z%20%2B15-2%2B7-2%2B2%3D38)
![z +20=38](https://tex.z-dn.net/?f=z%20%2B20%3D38)
Collect like terms
![z =-20+38](https://tex.z-dn.net/?f=z%20%3D-20%2B38)
![z =18](https://tex.z-dn.net/?f=z%20%3D18)
Students with one subject is then calculated as:
![1\ subject = x+y+z](https://tex.z-dn.net/?f=1%5C%20subject%20%3D%20x%2By%2Bz)
![1\ subject = 12 + 28 + 18](https://tex.z-dn.net/?f=1%5C%20subject%20%3D%2012%20%2B%2028%20%2B%2018)
![1\ subject = 58](https://tex.z-dn.net/?f=1%5C%20subject%20%3D%2058)
Your answer is 12.41x - 11.8
Answer:
ahhhhhhhhhhhh too muchhhhhhhhhhhhhh
Step-by-step explanation: