Answer:
the 95th percentile for the sum of the rounding errors is 21.236
Step-by-step explanation:
Let consider X to be the rounding errors
Then; 
where;
a = -0.5 and b = 0.5
Also;
Since The error on each loss is independently and uniformly distributed
Then;

where;
n = 2000
Mean 







Recall:



For 95th percentile or below





From Normal table; Z > 1.645 = 0.05




the 95th percentile for the sum of the rounding errors is 21.236
Answer:
D -13/35 ( negative 13/35 )
Step-by-step explanation:
4/5 + x = 3/7
Convert to equivalent fractions with a common denominator:
28/35 + x = 15/35
Subtract 28/35 from both sides
x = - 13/35
Answer:
760,000
Step-by-step explanation:
759,993
we round 993 up to 1,000
Answer:
I believe one batch is 2 eggs which means a batch and 1/2 is 3 eggs
Answer:
52
Step-by-step explanation:
SA=2*4*3+2*4*2+2*3*2=24+16+12=52