Answer:
50kg.m/s
Explanation:
In order to find momentum you must use the formula P=mv
p= momentum
m=mass
v= velocity
so in other words, momentum= mass times velocity
or in this case, momentum= 10 times 5 :)
Acceleration means speeding up, slowing down, or changing direction. The graph doesn't show anything about direction, so we just have to examine it for speeding up or slowing down ... any change of speed.
The y-axis of this graph IS speed. So the height of a point on the line is speed. If the line is going up or down, then speed is changing.
Sections a, c, and d are all going up or down. Section b is the only one where speed is not changing. So we can't be sure about b, because we don't know if the track may be curving ... the graph can't tell us that. But a, c, and d are DEFINITELY showing acceleration.
Answer:
![\frac{F_1}{F_2} =\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BF_1%7D%7BF_2%7D%20%3D%5Cfrac%7B1%7D%7B2%7D)
Explanation:
Assuming the we have to find ratio maximum forces on the mass in each case
we know that in a spring mass system
F= Kx
K= spring constant
x= spring displacement
Case 1:
![F_1=2k\times d](https://tex.z-dn.net/?f=F_1%3D2k%5Ctimes%20d)
case 2:
![F_2=2k\times 2d](https://tex.z-dn.net/?f=F_2%3D2k%5Ctimes%202d)
therefore, ![\frac{F_1}{F_2} = \frac{2K\times d}{2K\times 2d}](https://tex.z-dn.net/?f=%5Cfrac%7BF_1%7D%7BF_2%7D%20%3D%20%5Cfrac%7B2K%5Ctimes%20d%7D%7B2K%5Ctimes%202d%7D)
![\frac{F_1}{F_2} =\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BF_1%7D%7BF_2%7D%20%3D%5Cfrac%7B1%7D%7B2%7D)