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BartSMP [9]
3 years ago
12

Just for fun, a person jumps from rest from the top of a tall cliff overlooking a lake. in falling through a distance h, she acq

uires a certain speed v. assuming free-fall conditions, how much farther must she fall in order to acquire a speed of 2v? express your answer in terms of h.
b. would the answer to part
a. be different if this event were to occur on another planet where the acceleration due to gravity had a value other than 9.80 m/s2? explain.
Physics
1 answer:
RideAnS [48]3 years ago
4 0
For this we need to use several formulas:
v = a*t
This simply means that after 1 second we will have some speed and if we double time, speed will double as well.

But, relation time-traveled distance isn't linear. Traveled distance we calculate:
s = 1/2*a*t^2                we can say that h=s
so if we double time, traveled distance will increase 4 times because of square relation between time and traveled distance.

New traveled distance (h2) will be: h2=4*h

b)  Because distance depends on gravity acceleration in free fall h2 will certainly change but the relation h2=4*h will remain the same.
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3 years ago
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Boyle's Law mainly involves _______.
goblinko [34]
Your answer is B, gases
6 0
4 years ago
What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?
sveta [45]
Momentum = (mv). 
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8 0
3 years ago
1pt A cannon fires a 5-kg ball horizontally from a
Klio2033 [76]

Answer: Both cannonballs will hit the ground at the same time.

Explanation:

Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.

then the acceleration equation is only on the vertical axis, and can be written as:

a(t) = -(9.8 m/s^2)

Now, to get the vertical velocity equation, we need to integrate over time.

v(t) = -(9.8 m/s^2)*t + v0

Where v0 is the initial velocity of the object in the vertical axis.

if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s

and:

v(t) = -(9.8 m/s^2)*t

Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)

And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.

You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)

7 0
3 years ago
Question 14 (1 point)
Karo-lina-s [1.5K]

Answer:

car travel

precipitation

O temperature

Explanation:

Jet streams which is the ability of the object to move at a high speed due to its power is common among some given set of objects. Some are powered by the objects fuel while others are entirely different.

The above given options are actually affected by the jet streams.

5 0
3 years ago
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