Answer:
12m/s
Explanation:
v^2=u^2+2as
v=?
u=0 (the dish was stationary before it fell)
a=9.81 m/s^2 (acceleration due to gravity/freefall)
s=1.5m (the drop height)
So: v^2=0+2.9.81.1.5 = 144.35415
and therefore v=sqrt 144.35415
12x12=144 so I'd say v=12m/s
Answer:
Explanation:
Force on q due to Q
= k Qq / ( a² + d²)
x component
= k Qq / ( a² + d²) x d /√ ( a² + d²)
F = kQq d/ ( a² + d²)³/²
differentiating F with respect to d
dF / Dd = kQq [ d. -3/2 ( a² + d²)⁻⁵/² 2d + ( a² + d²)⁻³/²]=0 for maximum F
- 3d² / ( a² + d²) + 1 = 0
a² + d² = 3 d²
a² = 2d²
d = a / √2
Answer:
τ = (7.96 x 10⁴ m⁻³)T
This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.
Explanation:
The maximum allowable shear stress on the solid shaft can be given by the torsional formula as follows:
τ = Tc/J
where,
τ = Maximum Allowable Shear Stress = ?
T = Maximum Torque Applied to the Shaft
c = maximum distance from center to edge = radius in this case = 20 mm = 0.02 m
J = Polar Moment of inertia = πr⁴/2 = π(0.02 m)⁴/2 = 2.51 x 10⁻⁷ m⁴
Therefore,
τ = T(0.02 m)/(2.51 x 10⁻⁷ m⁴)
<u>τ = (7.96 x 10⁴ m⁻³)T</u>
<u>This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.</u>
Answer:
KE1 = 1/2 M V^2
KE2 = 1/2 M (2*V)^2
KE2 = 4 KE1
If stopping distance is proportional to the original KE then the stopping distance is 4 times great for the car moving at 2 * V
Hey there. cOvalent bonds consisting sharing of electrons, generally between non-metals, in order to gain 8 electrons, each atom. As for metals, their bond is metallic and more a non-metal+metal, it is ionic, as the metal loses and th non-metal gains electrons. Methane, made up of two non-metals, hydrogen and Carbon are a typical example of a covalent bond. As carbon adds his 4 electrons to the 4 of Hydrogen, by octet rule, it ends up with 8 electrons around it. Hence, the answer is B. Hope you understood it.
