When a fluid flows over an object, the "friction drag": __________.A.is the drag due to the shear stress only. B. depends only o
1 answer:
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When an object absorbs an amount of energy equal to Q, its temperature raises by 
following the formula
where m is the mass of the object and
is the specific heat capacity of the material.
In our problem, we have
, 
and 
, so we can re-arrange the formula and substitute the numbers to find the specific heat capacity of the metal:
where m is the mass of the object and
In our problem, we have
Answer:
= 0.331 J / g ° C
Explanation:
We have a calorimetry exercise where all the heat yielded by one of the components is absorbed by the other.
Heat ceded Qh = m1 ce1 ( -
)
Heat absorbed Qc = m2 ce2 ( - T₀)
Body 1 is metal and body 2 is water . Where m are the masses of the two bodies, ce their specific heat and T the temperatures
Qh = Qc
m₁ (
-
) = m₂
(
- T₀)
we clear the specific heat of the metal
= m₂
(
- T₀) / (m₁ (
-
))
= 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))
= 209.2 (9.36) / (75 78.85)
= 1958.11 / 5913.75
= 0.331 J / g ° C