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2 answers:
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Answer:
Range,
Explanation:
The question deals with the projectile motion of a particle mass M with charge Q, having an initial speed V in a direction opposite to that of a uniform electric field.
Since we are dealing with projectile motion in an electric field, the unknown variable here, would be the range, R of the projectile. We note that the electric field opposes the motion of the particle thereby reducing its kinetic energy. The particle stops when it loses all its kinetic energy due to the work done on it in opposing its motion by the electric field. From work-kinetic energy principles, work done on charge by electric field = loss in kinetic energy of mass.
So, [tex]QER = MV²/2{/tex} where R is the distance (range) the mass moves before it stops
Therefore {tex}R = MV²/2QE{/tex}
Answer:
The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.
Explanation:
We can calculate the speed of the train using the Doppler equation:
Where:
f₀: is the emitted frequency
f: is the frequency heard by the observer
v: is the speed of the sound = 343 m/s
: is the speed of the observer = 0 (it is heard in the town)
: is the speed of the source =?
The frequency of the train before slowing down is given by:
(1)
Now, the frequency of the train after slowing down is:
(2)
Dividing equation (1) by (2) we have:
(3)
Also, we know that the speed of the train when it is slowing down is half the initial speed so:
(4)
Now, by entering equation (4) into (3) we have:
By solving the above equation for we can find the speed of the train after slowing down:
Finally, the speed of the train before slowing down is:
Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.
I hope it helps you!