Answer:
22.36 rad
Explanation:
Applying,
ω = θ/t.............. Equation 1
Where ω = angular velocity, θ = angular displacement of the baseball, t = time
make θ the subject of the equation
θ = ωt............... Equation 2
From the question,
Given: ω = 350 rev/min = 350(0.10472) = 36.652 rad/s, t = 0.61 s
Substitute these values into equation 1
θ = 0.61(36.652)
θ = 22.36 rad
Hence the angular displacement of the baseball is 22.36 rad
Answer:


Explanation:
d = Diameter of column = 0.5 inch
= Area of concrete = 
The strain in the system is conserved

Now


Stress is given by

The stress in the steel is 

The stress in the steel is 
Answer:
There are 602 calories in 10 ounces of Ground Beef (85% Lean / 15% Fat). serving sizes of Ground Beef
Explanation:
hope this helps if not please let me now
The tension, T, in each rope is T= mg/2Sinθ
<h3>What is tension force?</h3>
Tension refers to the pulling force in a string which acts in an opposite direction to the force pulling on it.
The tension in each of the ropes are equal since they both make the same angle with the vertical.
Assume the angle the ropes make with the vertical are both θ.
Let the tension in each be T₁ and T₂
Also, T₁ = T₂ = T
T₁Sinθ + T₂Sinθ = mg
2TSinθ = mg
T = mg/2Sinθ
Therefore, the tension, T, in each rope is T = mg/2Sinθ
Learn more about tension at: brainly.com/question/14336853
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Answer:
Patm or the presion at the top is equal to 110977.28[Pa]
Explanation:
First we must define the absolute pressure value, which is equal to the sum of the atmospheric pressure plus the manometrial pressure.
![P_{abs} = P_{atm}+P_{man}\\where:\\P_{abs}=122000[Pa]](https://tex.z-dn.net/?f=P_%7Babs%7D%20%3D%20P_%7Batm%7D%2BP_%7Bman%7D%5C%5Cwhere%3A%5C%5CP_%7Babs%7D%3D122000%5BPa%5D)
Now we can find the manometric pressure.
![P_{man} = density*g*h\\where:\\density = 921[kg/m^3]\\g = gravity = 9.81[m/s^2]\\h = depth = 1.22[m]](https://tex.z-dn.net/?f=P_%7Bman%7D%20%20%3D%20density%2Ag%2Ah%5C%5Cwhere%3A%5C%5Cdensity%20%3D%20921%5Bkg%2Fm%5E3%5D%5C%5Cg%20%3D%20gravity%20%3D%209.81%5Bm%2Fs%5E2%5D%5C%5Ch%20%3D%20depth%20%3D%201.22%5Bm%5D)
![P_{man} = 921*9.81*1.22\\ P_{man}= 11022.71[Pa]](https://tex.z-dn.net/?f=P_%7Bman%7D%20%3D%20921%2A9.81%2A1.22%5C%5C%20P_%7Bman%7D%3D%2011022.71%5BPa%5D)
Therefore:
![P_{atm} = P_{abs} - P_{man} \\P_{atm} = 122000 - 11022.71\\P_{atm}= 110977.28[Pa]](https://tex.z-dn.net/?f=P_%7Batm%7D%20%3D%20%20P_%7Babs%7D%20-%20P_%7Bman%7D%20%5C%5CP_%7Batm%7D%20%3D%20122000%20-%2011022.71%5C%5CP_%7Batm%7D%3D%20110977.28%5BPa%5D)