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Marina CMI [18]

4 years ago

13

HELP PLEASE: According to Le Chatelier's principle, which of the following changes will shift the following equilibrium reaction

to the left:
N2(g) + 3 H2(g) ⟷ 2 NH3(g) + 22 kcal

2 answers:

Eva8 [605]4 years ago

8 0

Answer:

n2 g

Step-by-step explanation:

because use ur common senve

Kaylis [27]4 years ago

3 0

Answer:

n2g is the answer hope this HELP

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What is 6 3/4 x 3/5<br><br> A) 54/20<br><br> B) 75/12<br><br> C) 81/20<br><br> D) 9/4

steposvetlana [31]

The answer you are looking for is C my friend

8 0

3 years ago

Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A

Vlad [161]

Answer:

$y(x)=sin(2x)+2cos(2x)$

Step-by-step explanation:

$y''+4y=0$

This is a homogeneous linear equation. So, assume a solution will be proportional to:

$e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda$

Now, substitute $y(x)=e^{\lambda x}$ into the differential equation:

$\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0$

Using the characteristic equation:

$\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0$

Factor out $e^{\lambda x}$

$e^{\lambda x}(\lambda ^2 +4) =0$

Where:

$e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda$

Therefore the zeros must come from the polynomial:

$\lambda^2+4 =0$

Solving for $\lambda$ :

$\lambda =\pm2i$

These roots give the next solutions:

$y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}$

Where $c_1$ and $c_2$ are arbitrary constants. Now, the general solution is the sum of the previous solutions:

$y(x)=c_1 e^{2ix} +c_2 e^{-2ix}$

Using Euler's identity:

$e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)$

$y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\$

Redefine:

$i(c_1-c_2)=c_1\\\\c_1+c_2=c_2$

Since these are arbitrary constants

$y(x)=c_1sin(2x)+c_2cos(2x)$

Now, let's find its derivative in order to find $c_1$ and $c_2$

$y'(x)=2c_1 cos(2x)-2c_2sin(2x)$

Evaluating $y(0)=2$ :

$y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2$

Evaluating $y'(0)=2$ :

$y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1$

Finally, the solution is given by:

$y(x)=sin(2x)+2cos(2x)$

5 0

4 years ago

in how many ways can a supermarket chain select 3 out of 12 possible sites for construction of a new supermarket?

ki77a [65]

12x11x10 is 1320
In 1320 ways! Omg!

3 0

3 years ago

Read 2 more answers

Can somebody help me with these problems please

const2013 [10]

Answer:

<h3> $\huge\sf{Solutions :- }$ </h3>

<h3>7. Cos Z </h3>

=> Cos theta = Base /Hypotenuse

=> Cos Z = 30/50 => 3/5

★ So, Option <u>B) 3/5 </u> is a correct answer.

_______________________

<h3>8. Cos X </h3>

=> Cos theta = Base/Hypotenuse

=> Cos X = 12/37

★ So, option <u>D)</u><u> </u><u>1</u><u>2</u><u>/</u><u>3</u><u>7</u> is a correct answer.

________________________

<h3>9. Sin Z</h3>

=> Sin theta = Perpendicular/Hypotenuse.

Sin Z = 16/20 => 4/5

★ So, option <u>C)</u><u> </u><u>4</u><u>/</u><u>5</u> is a correct answer

<h3>_____________________</h3>

<h3>10. Sin Z </h3>

=> Sin theta = Perpendicular/Hypotenuse

Sin Z = 48/50 => 24/25

★ So, option <u>A)</u><u>2</u><u>4</u><u>/</u><u>2</u><u>5</u> is correct answer

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8 0

2 years ago

Svetlana's hair is 444 centimeters long. Her hair grows 1.51.51, point, 5 centimeters per month. Svetlana wants her hair to grow

GREYUIT [131]

For this item, I assume that Svetlana's hair is 4 cm long and she wanted it to be at least 7 cm long.
We let x be the number of months it will take for her hair to be 7 cm long. The sum of the product of x and the rate and the initial length should be at least 7. Mathematically,
1.51x + 4 ≤ 7

4 0

4 years ago