Select the correct answer.
2 answers:
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Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that,
So, the <u>speed of Pratap with the current</u> will be: miles/hour
and the <u>speed of Pratap against the current</u> will be: miles/hour.
Suppose, the rate of Pratap in still water is and the rate of current is
.
So, the equations will be........
Adding equation (1) and (2) , we will get......
Now, plugging this into equation (1), we will get.....
Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
common difference is
3.6 - 5.8 = -2.2
let T1 = 5.8
T2 = 3.6
assuming we are to find T2
T2 = T(2-1) -2.2
= T1 -22
= 5.8 -2.2
= 3.6