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alisha [4.7K]
3 years ago
5

Need help on these 2 questions please????? Hurry

Physics
1 answer:
fredd [130]3 years ago
3 0

Answer:

Question 1 the anwser is 300 meters.  Question 2 the answer is speed.

is Explanation:

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Temperature of the resistor in an RC circuit. In this problem we will look at the temperature response of the resist
fomenos

RC circuit determines the capacitor's charging rate.

  • In RC (resistive and capacitive) circuits, a capacitor's time constant is the number of seconds required to charge it to 63.2% of the input voltage.
  • This duration is described by a single time constant. After two time constants, the capacitor will be charged to 86.5% of the input voltage.
  • The RC time constant, also referred to as tau, is the time constant (in seconds) of an RC circuit and is obtained by multiplying the circuit resistance (in ohms) by the circuit capacitance (in farads), This transient reaction time T is stated in terms of = R x C, where R is the resistor value in ohms and C is the capacitor value in farads.

Learn more about  RC circuits here brainly.com/question/13450553

#SPJ4.

4 0
1 year ago
Inyunirnhihirthithjitejreigjerwig
kiruha [24]
Inyunirnhihirthithjitejreigjerwig
6 0
2 years ago
Read 2 more answers
1. The farthest star listed in the chart is? Arcturus, Capella, Aldebaran, Pollux, Regulus, Castor
Pachacha [2.7K]

Answer:

Regulus

Explanation:

Which is 77.63 light years away

8 0
2 years ago
crowbar of 5 metre is used to lift an object of 800 metre if the effort arm is 200cm calculate the force applied​
Klio2033 [76]

Answer:

 F = 5226.6 N

Explanation:

To solve a lever, the rotational equilibrium relation must be used.

We place the reference system on the fulcrum (pivot point) and assume that the positive direction is counterclockwise

         F d₁ = W d₂

where F is the applied force, W is the weight to be lifted, d₁ and d₂ are the distances from the fulcrum.

In this case the length of the lever is L = 5m, t the distance desired by the fulcrum from the weight to be lifted is

d₂ = 200 cm = 2 m

therefore the distance to the applied force is

          d₁ = L -d₂

         d₁ = 5 -2

         d₁= 3m

we clear from the equation

          F = W d₂ / d₁

          W = m g

          F = m g d₂ / d₁

we calculate

      F = 800 9.8 2/3

      F = 5226.6 N

4 0
2 years ago
Un cuerpo suspendido en el aire es capaz de:
Rama09 [41]

Answer:

Explanation:

d

5 0
2 years ago
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