When the original resistor is replaced with 3 times more resistive material, the resistance of the circuit increases by factor of 3 and the current flowing in the cirucit decreases by a factor 3.
<h3>
Ohm's law</h3>
Ohm's law states that, the current flowing in a conductor is directly proportional to the potential across the conductor.
V = IR
where;
- I is the current in the circuit
- V is voltage
- R is the resistance
When the resistance increases, the current flowing in the circuit decreases.
When the original resistor is replaced with 3 times more resistive material, the resistance of the circuit increases by factor of 3 and the current flowing in the cirucit decreases by a factor 3.
Learn more about ohm's law here: brainly.com/question/231741
Answer:
A) G = m³/kg.s²
B) E = kg.m²/s²
Explanation:
A)
The given relation is:
F = Gm₁m₂/r²
where, the units of all variables are:
F = Force = kg.m/s²
m₁ = m₂ = mass = kg
r = distance = m
G = Gravitational Constant = ?
Therefore,
kg.m/s² = G(kg)(kg)/m²
(kg.m/s²)(m²/kg²) = G
<u>G = m³/kg.s²</u>
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B)
The given equation is:
E = mc²
where, the units of all variables are:
m = mass = kg
c = speed = m/s
E = Energy = ?
Therefore,
E = (kg)(m/s)²
<u>E = kg.m²/s²</u>
This is the correct answer, which is not present in any option.
Answer:
All of them: change velocity, accelerate, change position
Explanation:
We can answer this question by using Newton's second law:
F = ma
where
F is the net force on the object
m is the mass of the object
a is the acceleration
We notice that when there is an unbalanced force on the object, 
, and therefore
whcih means that the object will accelerate.
But acceleration is the rate of change of velocity, v:
And so,
which means that the object will change velocity.
If the object is changing velocity, this means that it is also moving: therefore, the position of the object must be changing, so also the option "change position" is correct.
Explanation:
Given that,
Radius of the circular loop, r = 3.5 cm = 0.035 m
(a) During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2 T to 0.5 T. Due to the change in the magnetic field, an emf will induced in it. The magnitude of induced emf is given by :
So, the magnitude of the emf induced in the loop during the time interval is 
.
(b) The negative sign shows that the direction of induced emf in the loop is in anitclockwise direction.
Answer: 0.25 seconds.
Explanation:
The yo-yo does 240 revolutions in one minute, and we know that one minute has 60 seconds, then the revolutions per second can be calculated as:
240 rev/60s = 4 rev/s, this will be the frequency of the yo-yo
The frequency is actually written as: f = 4 Hz = 4 s^-1
We want to find the period of this yo-yo.
The period is the duration of one cycle, and we have the relation:
f = 1/T
Where f is the frequency and T is the period, then:
T = 1/f
And we know the value of f, it is f = 4 s^-1
Then the period will be:
T = 1/(4 s^-1) = (1/4) s
Then the period of the yo-yo is 1/4 seconds = 0.25 seconds.
