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3 years ago

5

A car traveling on the taconic parkway travel 84 miles in two hours. What is the cars speed (a special type of rate) in miles pe

r hour?

2 answers:

Elza [17]3 years ago

3 0

I believe the car is going 42 miles per hour.

Mamont248 [21]3 years ago

3 0

The car is going 42mph

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Solve the following equation: 156 + (7 – 3) x 7 = A. 174 B. 184 C. 1,050 D. 1,120

V125BC [204]

Using BEDMAS you follow the structure of what processes you need to do in the right mathematical order.

In this case, Brackets first, multiplication second, then adding.

Therefore answer he answer is C 184

8 0

3 years ago

What’s 7= y-2/3 if you’re solving for y

Rus_ich [418]

Answer:

y = 23/3

Step-by-step explanation:

Simplify both sides of equation

7 = y + -2/3

Flip equation

y + -2/3 = 7

Add 2/3 to both sides

y + -2/3 + 2/3 = 7 + 2/3

y = 23/3

6 0

3 years ago

Stephen says that the numbers 38 and 40 are relatively prime. Explain why he is incorrect in making this statement. (make a good

Paha777 [63]

Answer:

He is incorrect in this statement because 38 and 40 both have factors, other than 1 x itself. Prime numbers are numbers the only have 1 factor pair, and that is 1 x itself. Factors are the numbers you multiply to get the end result, and an example is 10x4=40. The factors of 40 are 8x5, 4x10, 2x20, and of course, 1x40. The factors of 38 are 2x19, and 1x38.

8 0

3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by <em>b</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since <em>a/b</em> < <em>c/d</em>, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by <em>b/d</em> to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and <em>a/b</em> < <em>c/d</em> tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

5 0

3 years ago

Help me Guess just help please

Andrew [12]

Answer:

maybe 2 only?

Step-by-step explanation:

I'm just guessing but it sounds right

7 0

3 years ago

Read 2 more answers