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3 years ago

5

A car traveling on the taconic parkway travel 84 miles in two hours. What is the cars speed (a special type of rate) in miles pe

r hour?

2 answers:

Elza [17]3 years ago

3 0

I believe the car is going 42 miles per hour.

Mamont248 [21]3 years ago

3 0

The car is going 42mph

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It takes 33 pounds of seeds to completly plant a 6 acre field. how many acres can be planted per pound of seed

ahrayia [7]

If it takes 33 pounds of seeds to plant a 6 acre field;

6/33=2/11 or 0.1818

One pound of seeds would be able to plant 2/11 of an acre.

Hope I helped :)

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4 years ago

A cyclist rode at an average speed of 15 mph for 30 miles. How long was the ride? Question 6 options: 0.5 hours 1 hour 2 hours 3

Rus_ich [418]

Answer:

2 hours

Step-by-step explanation:

using the relationship

distance = speed × time, then

time = $\frac{distance}{speed}$ = $\frac{30}{15}$ = 2 hours

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3 years ago

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Christopher mixes the letters s, e, l, e, c, t, e, and d thoroughly. without looking, allen draws one letter. expressed as a fra

natka813 [3]

There are 8 letters and 3 of them is a vowel.

P(not consonant) = P(vowel) = 3/8
A is the correct choice.

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3 years ago

Read 2 more answers

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

<em><u>Solution:</u></em>

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

<em><u>Use the following log rules</u></em>

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

Next

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

Next

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

Next

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

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3 years ago

How to find unpaid balance

koban [17]

Take the cost of the item. Subtract how much you already paid from the cost of the item. Then boom! You got your answer. Hope I helped.

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3 years ago