A box contains five balls numbered 1, 2, 3, 4, 5. Three balls are drawn randomly at the same time from the box.

1 answer:

6 0

The possible outcomes could be:{123,124,125,134,135,145,234,235,245,345}
Their sums are as follows respectively:{6,7,8,8,9,10,9,10,11,12}=7
The odd sums are{7,9,11}=3
the probability of the sum being odd is 3/7
b.The number of outcomes are 10
the number of outcomes in which L is 4 are 3
So the probability of L being 4 is 3/10

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Perform the indicated operation. (-7) • (-5) -12 35 12 -35

Flauer [41]

Hi,

Equation:

$- 7 \times (- 5)$

Multiplying two negatives equals a positive.

$( - ) \times ( - ) = ( + )$

Now equation looks like:

$7 \times 5 = 35$

Hope this helps.
r3t40

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