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PIT_PIT [208]
3 years ago
6

Who would be the most likely audience for Jack London's story?

Mathematics
2 answers:
ki77a [65]3 years ago
8 0

Answer: general public

sergey [27]3 years ago
5 0

Answer:

A is the answer

Step-by-step explanation:

You might be interested in
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
Which functions domain consist of all real numbers except -2
amm1812

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Cameron has 2 video game holder stands each can hold 2 rows of 20 games write and evaluate a numerical expression to find the to
Aleksandr [31]

Answer:

so this would be the equation

2(2*10)=v

So the number on the outside is the number of stands, the second 2 is for the two rows, and the 10 is the games. I did this because its two rows and combined they make 20 games. It took me a little to figure that out.

This shows the number of games total in both holders.


5 0
3 years ago
Which is another way to check the sum 52+23+10+78
kotykmax [81]
52+23=75
10+78=88 
88+75=163
that's one way 

7 0
3 years ago
What is the total area of the figure below?
faltersainse [42]

Step-by-step explanation:

As we know that,

In area of triangle , breadth =6inch,similarily ,height =8inch

now ,

Area of triangle = 1/2 ×b×h

= 1/2 × 8 ×6

=24inch^2

also,

In another figure,we can say

a=10 inch,b=16 inch and h=9 inch

similarly,

Area of trapizium = 1/2 h(a+b)

= 1/2 ×9(10+16)

=9/2 ×26

=9×13

=117inch^2

now ,

total area of figure =117 +24 =141inch^2

therefore,total area of figure is 141 inch^2

4 0
3 years ago
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