Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
Answer:
B
Step-by-step explanation:
Answer:
so this would be the equation
2(2*10)=v
So the number on the outside is the number of stands, the second 2 is for the two rows, and the 10 is the games. I did this because its two rows and combined they make 20 games. It took me a little to figure that out.
This shows the number of games total in both holders.
52+23=75
10+78=88
88+75=163
that's one way
Step-by-step explanation:
As we know that,
In area of triangle , breadth =6inch,similarily ,height =8inch
now ,
Area of triangle = 1/2 ×b×h
= 1/2 × 8 ×6
=24inch^2
also,
In another figure,we can say
a=10 inch,b=16 inch and h=9 inch
similarly,
Area of trapizium = 1/2 h(a+b)
= 1/2 ×9(10+16)
=9/2 ×26
=9×13
=117inch^2
now ,
total area of figure =117 +24 =141inch^2
therefore,total area of figure is 141 inch^2