What is 7-( 5-4x )< 2 ( 3x+8 )

Using triangle A B C as the pre-image and the origin as the center of dilation, which coordinate point is not a coordinate of a

Ostrovityanka [42]

Answer:

The correct option is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12).

Step-by-step explanation:

We are given the coordinates of the point A,B and C of the triangle ΔABC as:

A(-1,3) , B(2,1) and C(-2,-1).

Now it is given that there is dilation of this triangle about the origin with a scale factor of 4.

This means that the change in the coordinates after the transformation is given by the rule:

(x,y) → (4x,4y)

As A → A' , B → B' and C → C'

Hence the coordinates A',B' and C' are given by:

A' are (4×-1,4×3)=(-4,12)

B' are (4×2,4×1)=(8,4)

and C' are (4×-2,4×-1)=(-8,-4).

<em>Hence the coordinate point which is not a coordinate of dilation is:</em>

<em>begin ordered pair 4 comma 12 end ordered pair i.e. (4,12)</em>

3 0

3 years ago

1. 1.5 ÷ 1.2

kirill115 [55]

Answer:

1. 25

2. 5.7

3. 10.7

4. 204

5. 100.5

Step-by-step explanation:

calculator

6 0

3 years ago

Reese is selling lemonade at the parade. He gets to keep 10% of the money he collects. A large lemonade is $7.00 and a small lem

jeka94

Answer:

We conclude that the simplified expression is:

$0.10\left(7l\:+\:2s\right)=0.7l+0.2s$

Step-by-step explanation:

Given the expression

$0.10\left(7l\:+\:2s\right)$

Apply the distributive law: a(b+c) = ab+ac

a = 0.1, b = 7l, c = 2s

$0.10\left(7l\:+\:2s\right)=0.1\cdot \:7l+0.1\cdot \:2s$

$=7\cdot \:0.1l+2\cdot \:0.1s$

$=0.7l+0.2s$

Therefore, we conclude that the simplified expression is:

$0.10\left(7l\:+\:2s\right)=0.7l+0.2s$

4 0

3 years ago

What percent of 3 is 1.8

rusak2 [61]

Answer:

60%

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Wasserman (1989) studied a process for the manufacturing of steel bolts. Historically, these bolts have a mean thickness of 10.0

zalisa [80]

Answer:

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

Step-by-step explanation:

To solve this question, we use the central limit theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 10, \sigma = 1.6, n = 5, s = \frac{1.6}{\sqrt{5}} = 0.7155$

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

7 0

4 years ago