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2 years ago

Plz help asap. I really need it

Mathematics

2 answers:

Pavlova-9 [17]2 years ago

4 0

The anser is a as in apple

Rus_ich [418]2 years ago

4 0

The correct answer is a

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Segment Y prime Z prime has endpoints located at Y'(0, 3) and Z'(−6, 3). segment YZ was dilated at a scale factor of 3 from the

Klio2033 [76]

Answer:

D. Segment YZ is located at Y(0,1) and Z(−2,1) and is one-third the size of segment Y'Z'

Step-by-step explanation:

When you dilate a point by a factor of x from the origin, you multiply its coordinates by the same factor.

Thus, if the coordinates of the original point are (1,2) and the scale factor is 3, those of its image are (3,6).

If Y'Z' has endpoints at Y'(0,3) and Z'(-6,3) and was dilated by a factor of 3, the coordinates of the endpoints of the pre-image were ⅓ those of the image.

The figure below shows the segments YZ and Y'Z'.

5 0

3 years ago

Find the area of shaded region

Anastaziya [24]

Answer: 107 units.

Step-by-step explanation: To find the area of the first box, you multiply the side lengths, which in this case are 5 by 7 to get 35. Then you find the area of the second box by multiplying 8 * 10 which is 80 so the total area of everything is 115 units. Then you subtract the non - shaded region which is 2 * 4 units. So after subtracting 115 - 8, you get your final answer of 107 units.

4 0

3 years ago

Read 2 more answers

A college administration has conducted a study of 166 randomly selected students to determine the relationship between satisfact

Annette [7]

It would help if we represent the information in form of two-ways table as shown below

The number of students who are not on probation is 104 students
There are 23 students who are not on probation and is satisfied is 81 students

The probability of students not on probation and is satisfied is 81/104

5 0

3 years ago

Please help me with this

dem82 [27]

Answer:

I believe it is 49.425

Step-by-step explanation:

You just add all the numbers then divide it by how many numbers there are.

5 0

3 years ago

Read 2 more answers

How many equivalence relations are there on the set 1, 2, 3]?

Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0

3 years ago