Question

While heating two different samples of water at sea level, one boils at 102°c and one boils at 99.2°c. calculate the percent error for each sample from the theoretical 100.0°c?

Answer 1

Answer: The percentage error of sample 1 of water is 2 % and that of sample 2 is 0.8 %

Explanation:

To calculate the percentage error, we use the equation:

$\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100$      ......(1)

• For sample 1:

Experimental value of temperature = 102°C

Theoretical value of temperature = 100.0°C

Putting values in equation 1, we get:

$\%\text{ error}=\frac{|102-100|}{100}\times 100\\\\\%\text{ error}=2\%$

• For sample 2:

Experimental value of temperature = 99.2°C

Theoretical value of temperature = 100.0°C

Putting values in equation 1, we get:

$\%\text{ error}=\frac{|99.2-100|}{100}\times 100\\\\\%\text{ error}=0.8\%$

Hence, the percentage error of sample 1 of water is 2 % and that of sample 2 is 0.8 %

Answer 2

To find: Sample error in percent
 Solution:
 Formula:
((Experimental value-theoretical value)/theoretical value)*100
 where, theoretical value = 100°c
 and, experimental value = 102°c (sample 1) 99.2°c (sample 2)
 Sample error (in percentage) when boiling level was 102°c = ((102°c-100°c)/100°c)*100 = 2%
 Sample error (in percentage) when boiling level was 99.2°c = ((99.2°c-100°c)/100°c)*100 = -0.8%