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ElenaW [278]
3 years ago
11

You perform a test cross of the dihybrid AaBb and score the phenotypes of 1000 progeny. Assuming independent assortment, how man

y of the progeny do you expect to display the dominant phenotype for both the A and B genes?

Biology
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

4

Explanation:

<em>The number of progeny expected to display the dominant phenotype for both the A and B genes should be  4.</em>

<u>A test cross usually involves crossing an individual whose zygosity is in doubt with an individual that is recessive for both alleles so as to ascertain the zygosity of the former.</u> Hence, for a test cross involving AaBb:

             AaBb     x     aabb

Progeny:

4 AaBb

4 Aabb

4 aaBb

4 aabb

<em>Therefore, the number of progeny expected to display the dominant phenotype for both the A and B genes is 4.</em>

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Firstly the question is incomplete as an option is not there.

Why do the number of organisms in a group change from the first step to the last step of a dichotomous key?

a. The number of organisms decreases because the number of common characteristics of the organisms in a group increases.

b. The number of organisms increases because the number of common characteristics of the organisms in a group increases.

c. The number of organisms is cut in half because the number of common characteristics of the organisms in a group decreases by half in the last step.

d. The number of organisms stays the same because the number of common characteristics of the organisms in a group decreases by half in the last step.

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<h3>What is the use of the dichotomous key?</h3>

The use of dichotomous keys are :

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Hence concluded that the dichotomous key has a number of organisms increases because the number of common characteristics of the organisms in a group increases.

To learn more about dichotomous keys refer to the link :

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