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faltersainse [42]
3 years ago
6

Pronghorn Corp. has the following beginning-of-the-year present values for its projected benefit obligation and market-related v

alues for its pension plan assets.
Projected Plan
Benefit Assets
Obligation Value
2013 2,000,000 $1,900,000
2014 2,400,000 2,500,000
2015 2,950,000 2,600,000
2016 3,600,000 3,000,000
The average remaining service life per employee in 2016 and 2017 is 10 years and in 2018 and 2019 is 12 years. The net gain or loss that occurred during each year is as follows: 2016, $288,400 loss; 2017, $92,700 loss; 2018, $11,330 loss; and 2019, $25,750 gain. (In working the solution, the gains and losses must be aggregated to arrive at year-end balances).
Using the corridor approach, compute the amount of net gain or loss amortized and charged to pension expense in each of the four years, setting up an appropriate schedule.
Business
1 answer:
galina1969 [7]3 years ago
5 0

Answer:

Year Minimum Amortization of Loss

2016 $0

2017 $3,840

2018 $ 6,855

2019 $1,811.25

Explanation:

Computation of the amount of net gain or loss amortized and charged to pension expense in each of the four years.

Corridor and Minimum Loss Amortization

Year 2016

Projected Benefit Obligation (a) $2,000,000

Plan Assets $1,900,000

10%Corridor 200,000

(10%×$2,000,000)

AccumulatedOCI (G/L) (a) $0

Minimum Amortization of loss $0

Year 2017

Projected Benefit Obligation (a) $2,400,00

PlanAssets $2,500,000

10%Corridor 250,000

(10%×$2,500,000)

AccumulatedOCI (G/L) (a) $288,400

Minimum Amortization of loss $3,840 (b)

Year 2018

Projected Benefit Obligation (a) $2,950,000

PlanAssets $2,600,000

10%Corridor 295,000

(10%×$2,950,000)

AccumulatedOCI (G/L) (a) $377,260(c)

Minimum Amortization of loss $6,855 (d)

Year 2019

Projected Benefit Obligation (a) $3,600,000

PlanAssets $3,000,000

10%Corridor 360,000

(10%×$3,600,000)

AccumulatedOCI (G/L) (a) $381,735(e)

Minimum Amortization of loss $1,811.25 (f)

Workings

A. As of the beginning of the year

B. ($288,400-$250,000)÷10 years

=$38,400÷10 years

=$3,840

C. ($288,400-$3,840+$92,700)

=$377,260

D.($377,260-$295,000)÷12 years

=$82,260÷12 years

=$6,855

E. $377,260-$6,855+$11,330

=$381,735

F. ($381,735-$360,000)÷12 years

=$21,735 ÷12 years

=$1,811.25

Hence,

Year Minimum Amortization of Loss

2016 $0

2017 $3,840

2018 $ 6,855

2019 $1,811.25

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Answer:

option (B) 25,000

Explanation:

Data provided in the question:

Fixed cost = $500,000 per year

Cost of wood and labor to manufacture one bat = $5

Selling price of the bat = $25

Now,

At breakeven, total cost equals to the total revenue

let the breakeven quantity be 'x'

thus,

$500,000 + $5x = $25x

or

$25x - $5x = $500,000

or

$20x = $500,000

or

x = 25,000

Hence,

the correct answer is option (B) 25,000

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Answer:

d. Are the most trustworthy signs of good management

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A solution was made by dissolving 800. 0 g of NaOH in 25,200 g of water. Calculate the morality, molality, and mole fraction of
maks197457 [2]

The morality, molality, and mole fraction of NaOH is mathematically given as

  1. morality= 4 ppm
  2. molality=0.7936m
  3. x1 = 0.152

What are the morality, molality, and mole fraction of NaOH?

Question Parameters:

A solution was made by dissolving 800. 0 g of NaOH in 25,200 g of water.

Generally, the equation for the Molality   is mathematically given as

molality = (mass / molar mass) x (1/ weight of solvent kg)

Therefore

M= (800 /40) x (1 /25.2)

M=0.7936m

Therefore

m= 10 x 18 / 1000

m= 0.18

Hence

x1 = 0.18 - 0.18 x1

1.18 x1 = 0.18

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Where the mole fraction is x1 = 0.152 The mass is

m= (800 / 800 + 2000) x 1000

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Hence the morality

molality = mg /L

molality= 8000 x 10^-3 / 2 L

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In conclusion, the morality, molality, and mole fraction of NaOH are given respectively as

morality= 4 ppm

molality=0.7936m

x1 = 0.152

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