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irakobra [83]
3 years ago
8

How does using a bar diagram help you in predicting the solution to ratio and rate problems?

Mathematics
2 answers:
MatroZZZ [7]3 years ago
5 0

Solution:

Suppose The income of a person is $12,000 and amount spent on family expenditure , fare,and outing are 6,000 and 1,000 and $ 500 respectively.So, Ratio of income and money spent can be represented on a bar, which helps in observing as well as predicting the solution easily.

Now, coming to rate problem  If the two quantities are proportional suppose  Speed of a person in different interval of time is given ,and we represent these distances on a bar Diagram, we can easily calculate as well as predict the solution of these kind of problems.

So,ratio and rate are actually the same thing ,that is they gives a fixed value when two quantities are in comparison ,and when plotted on a bar diagram helps in determining as well as predicting the solution of the problem.


Law Incorporation [45]3 years ago
3 0
<span>Bar graph display directly the varibales which are the rate and ratio of the numbers to visualize and display the results, these contrasting the different outcomes. On the contrary, histogram is used in grouped frequency parameters. Moreover, as little as the given five parameters or data set this will be ineffective and will result to a bar graph only and basically, the suited option is the aforementioned vertical graph to display the numbers. To expound on the definition of histogram it is used when the frequency is grouped. For example the data set of 1-5, 6-10, 11-15 and 16-20 this now can be used and applied to illustrate histogram because of the number and quantity of the given data.<span>
</span></span>
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Mars2501 [29]

2y-x=3/4(-y+1)first distribute

2y-x=-3/4y+3/4 get the y on one side

2y-x+3/4y=3/4 add 3/4y to both sides

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Step-by-step explanation:

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nikdorinn [45]

Answer:

See explanation

Step-by-step explanation:

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Using long division, you can find that the real answer.

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In rectangle JKLM, JK is equal to 10 feet and MN is equal to 25 feet, find JL.
Snezhnost [94]

we know that

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