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2 years ago

If ori has 10 mangos and gives 20 mangos to lucy,how many mangos does ori need to give

Mathematics

1 answer:

serg [7]2 years ago

4 0

Ori needs to give 10 more mangos or else lucy will only get 10

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The graph of a quadratic relationship is in the shape of a parabola. Parabolas are symmetric arcs and are useful for modeling re

zhuklara [117]

Answer:

The arcs on the Golden Gate Bridge.

Explanation:

I think about the Golden Gate Bridge, which is a suspension bridge.

As in any suspension bridge, a long cable is supported by two large supports.

The cable falls from a support, in the form of a curve concave upwards, to a minimum point that is the vertex of the parabola, through which the axis of symmetry passes, and curves again upwards to ascend to the upper end of the other support.

As a unique feature of this parabolic arc you can tell that the the concavity is upward; the parabola open upward.

Also, you can tell that the parabola is vertical, which means that the axis of symmetry is vertical.

The symmetry is clear because to the curve to the left of the vertex is a mirror image of the curve to the right of the vertex.

6 0

3 years ago

Ruben bought 6 comic books for $21 dollars sign, 21. What was the cost for 1 comic book?

Lena [83]

Answer:

$3.5

Step-by-step explanation:

21/6=3.5

6 0

2 years ago

Read 2 more answers

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations.

Nostrana [21]

$x^3-27i=0$
$x^3=27i$
$x^3=27e^{i\pi/2}$
$x=\left(27e^{i\pi/2}\right)^{1/3}$
$x=3e^{i(\pi/2+2\pi k)/3}$
$x=3e^{i\pi(4k+1)/6}$

where $k\in\{0,1,2\}$ . This means you have

$x=3e^{i\pi/6}=\dfrac32(\sqrt3+i)$
$x=3e^{i5\pi/6}=\dfrac32(-\sqrt3+i)$
$x=3e^{i9\pi/6}=-3i$

as the solutions to the original equation.

4 0

3 years ago

Ashlyn is selling boxes of cookies for a fundraiser. If she raised $26 selling eight boxes, how much will she raise if she sells

allochka39001 [22]

She raises thirteen dollars

6 0

2 years ago

Read 2 more answers

If the given values in a right triangle are cos A =

Vlad1618 [11]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2

5 0

3 years ago