5:6 Hope this helps you!!
switting upwards this should help
Answer:
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Step-by-step explanation:
Given:
Length of diagonal = 9 in
Find:
Total length of iron needed to make the square frame and two diagonals.
Computation:
Area of square = 1/2(diagonal)²
Area of square = 1/2(9)²
Area of square = 40.5 in²
Area of square = Side × Side
40.5 in² = Side × Side
Side = 6.36 (approx)
Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)
⇒ (4 × 6.36) + (2 × 9)
⇒ (25.44) + (18)
⇒ 43.44 in
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Answer:
28%
Step-by-step explanation:
78th percentile means 78% scored less than/equal to you.
100 - 78 = 22%
The missing part is the proof ... hope it helped thank you you welcome have a frat day thanks bye adios amigo q to balls bin en too visa much's gracious yew me la peals pot too Ajax thanks yes what ever loll <span />
