Question

Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in the table. A cylinder. Model 1 radius: 14 cm height: 48 cm diagonal: 50 cm Model 2 radius: 6 cm height: 35 cm diagonal: 37 cm Model 3 radius: 20 cm height: 40 cm diagonal: 60 cm Model 4 radius: 24 cm height: 9 cm diagonal: 30 cm In which model does the lateral surface meet the base at a right angle? Model 1 Model 2 Model 3 Model 4

Answer 1

The model in which the lateral surface meets the base at right angle is : Model 1.

What is a lateral surface?

The lateral surface of an object is all surfaces  of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

$(50)^{2}$ = $(14)^{2}$ + $(48)^{2}$

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm  lateral height = 35cm

$(37)^{2}$ = $(35)^{2}$+ $(6)^{2}$

1369 = 1225 +36

1369 $\neq$ 1261

Model 3

Diagonal = 60cm, radius = 20cm  lateral height = 40cm

$(60)^{2}$ = $(20)^{2}$ + $(40)^{2}$

3600 = 400 + 1600

3600 $\neq$ 2000

Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

$(30)^{2}$ = $(24)^{2}$ + $(9)^{2}$

900 = 576 + 81

900 $\neq$ 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion,  the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

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Answer 2

Answer:

the answer is B have an amazing day

Step-by-step explanation: