Answer:
The number of liters of 50% antifreeze solution is 50 and the number of liters of 90% antifreeze solution is 150
Step-by-step explanation:
Let
x ----> number of liters of 50% antifreeze solution
y ----> number of liters of 90% antifreeze solution
we know that
50%=50/100=0.50
90%=90/100=0.90
80%=80/100=0.80
x+y=200
x=200-y ------> equation A
0.50x+0.90y=0.8(200) -----> equation B
substitute equation A in equation B and solve for y
0.50(200-y)+0.90y=160
100-0.50y+0.90y=160
0.40y=160-100
0.40y=60
y=150 liters
Find the value of x
x=200-y
x=200-150=50 liters
therefore
The number of liters of 50% antifreeze solution is 50
The number of liters of 90% antifreeze solution is 150
The only solution is (-3/2, 4)
read my attachment
Step-by-step explanation:
The longest side of a triangle cannot be longer than the sum of the two shorter sides. So if the 5cm and 12cm sides are the shorter sides, the third one cannot be longer than the 17cm. ... So 12cm is not longer than 5cm plus the length of the third side, and therefore the missing side cannot be shorter than 7cm.
On the bottom line, the 106 and number 1 make a straight line and needs to equal 180 degrees.
This means number 1 = 180-106 = 74 degrees.
Because x and y are parallel, the top outside angle is the same as number 1.
6x +8 = 74
Subtract 8 from both sides:
6x = 66
divide both sides by 6:
x = 66 / 6
x = 11
Now you have x, replace x in the equation for 7x-2 to find that angle:
7(11) -2 = 77-2 = 75 degrees.
The three inside angles need to equal 180 degrees.
Angle 2 = 180 - 74 - 75 = 31 degrees.
Answer:
Ok
Step-by-step explanation:
