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Misha Larkins [42]

3 years ago

5

Which answer choice correctly lists equivalent forms of the same number?

1 answer:

hram777 [196]3 years ago

7 0

Answer: B
Explanation:

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Could someone please help me with these systems. I have to use substitution.

FromTheMoon [43]

Isolate one term (x or y) in one of the equations

6x+6y=0
6x=-6y
X= -1y

Substitute x=-y into the other equation

-7(-y) + 2y =18

7y + 2y =18

9y=18

Y=2

Substitute y=2 into 6x+6y=0

6x + 6(2) = 0

6x + 12=0

6x= -12

X = -2

8 0

3 years ago

Help me solve this please

igomit [66]

The key word here is *square* in "square flower garden".

So we need to find the area of the flower garden, and subtract it from the overall area of the yard. The remainder will be how much grass covers the yard.

Area of the Square flower garden:
7.5 * 7.5 = 56.25

Area of the Entire yard:
25 * 18 = 450

450 - 56.25 = 393.75 square feet of grass

6 0

3 years ago

Solve the quadratic equation (2x-3)^2 = 6(3-2x)

LenKa [72]

Answer:

$x=\frac{3\sqrt{2}-3 }{2}$

$x=-\frac{3\sqrt{2}-3 }{2}$

Step-by-step explanation:

Open the brackets first:

$4x^2+9=18-12x$

Simplify:

$4x^2+12x-9=0$

It is determined that this can't be factored, so rewrite the equation so you can complete the square.

$x^2+3x=\frac{9}{4}$

Take the square of 1.5 and add it to both sides:

$x^2 + 3x+ \frac{9}{4} =\frac{9}4} +\frac{9}{4}$

Factor:

$(x+\frac{3}{2})^2=\frac{9}{2}$

$x+\frac{3}{2} = \frac{3\sqrt{2} }{2 }$

or $x+\frac{3}{2} =-\frac{3\sqrt{2} }{2}$

So $x=\frac{3\sqrt{2}-3 }{2}$

or $x=-\frac{3\sqrt{2}-3 }{2}$

5 0

3 years ago

What is the growth factor of y=70(2)^x

user100 [1]

Answer:

100% growth rate or it doubles

Step-by-step explanation:

This is of the form

y = ab^x

where a is the initial value and

b is the growth/decay factor

b>1 growth

b<1 decay

Since b>1 it is growth

We determine the growth rate by

b-1

2-1 =1

Multiply by 100%

1*100% = 100 % growth rate

3 0

3 years ago

Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths

Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e $(base)^2 + (Height)^2 = (Hypotenuse)^2$

For the given Lengths 7, 40 and 41

We need to check if

$7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2$

$Since \\7^2 + 40^2 = 1649\\and \\41^2 = 1681$

That means, $\\ 7^2 + 40^2 \neq 41^2$

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

$12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2$

Therefore given sides 12,16 and 20 can be the sides of right triangle.

7 0

3 years ago