Answer:
P(has 32 GB) = .382
Step-by-step explanation:
There are 75 + 95 + 42 + 63 = 275 total tablets
There are 42 + 63 = 105 tablets of 32 GB
P(has 32 GB) = 105/275 = .382
Note: Type "2^x" without quotes to indicate

When you graph this function, you'll see that we have the exponential curve sloping upward as x increases. The function increases upward without bound. In other words, it goes on forever upward. There are no restrictions on the "ceiling" so to speak of this function curve.
There is a floor though. The floor in this case is like an electric fence that the function never touches. It only gets closer. This is known as the "horizontal asymptote". In this case, the horizontal asymptote is the line y = 0 which lays perfectly over the x axis.
So because of this "fence", the function is bounded below. It does not go forever in the negative y direction.
Final Answer: Choice B) Bounded below
Answer: second Congress
Step-by-step explanation:
Short and sweet
Answer:-2/3
Step-by-step explanation:the problem is asking for the slope of (0,2) and(3,0). The formula for this problem is y2-y1 over x2-x1. And if your writing this formula down write it like a fraction with y on top and x on bottom. (x,y) (x2,y2). You take the 0 from the second set and the 2 from the first set and subtract them to get -2. Then you take the 3 from the sea d set and the 0 from the first set and you subtract them to get 3. That’s how you get the answer of -2/3.
9514 1404 393
Answer:
a) average rate = (total distance)/(total time)
b) Rave = 2·R1·R2/(R1 +R2)
c) cheetah's average rate ≈ 50.91 mph
Step-by-step explanation:
a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...
First leg distance: AB = 70·t1 ⇒ t1 = AB/70
Second leg distance: AB = 40·t2 ⇒ t2 = AB/40
The average rate is the ratio of total distance to total time:
average rate = (AB +AB)/(t1 +t2)
average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)
average rate = 560/11 = 50 10/11 . . . mph
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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.
b) For two rates over the same distance (as above), the average is their harmonic mean:
average rate = 2r1·r2/(r1+r2)
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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.